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galben [10]
3 years ago
7

Find the ratio if it is given that, a+3b/5= a-2b/

ula1" title="a+3b/5= a-2b/2" alt="a+3b/5= a-2b/2" align="absmiddle" class="latex-formula">2
Mathematics
2 answers:
AfilCa [17]3 years ago
8 0

Answer:

I don't kno the answer, but thx for the points

Step-by-step explanation:

ivolga24 [154]3 years ago
6 0

Answer:

dbhjnhygtfvbhnj

Step-by-step explanation:

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Solve:<br><br> 7 = x + 12<br> A) -19 <br> B) -5 <br> C) 4 <br> D) 5
DaniilM [7]

<em><u>Hello, there! :)</u></em>

<u><em>Answer:</em></u>

<u><em>x=-5 </em></u>

<u><em>B. -5</em></u>

<u><em>*The answer must have a negative sign.*</em></u>

Step-by-step explanation:

Definition of subtraction property of equality.

Subtraction property of equality is subtracting the same number from both sides of an equation does not change the equation.

a-c=b-c

First, you had to switch sides.

x+12=7

Then, you subtract by 12 from both sides of an equation.

x+12-12=7-12

And finally, simplify or solve.

7-12=-5

x=-5

Hope this helps!

Thanks!

-Charlie

:)

8 0
3 years ago
Simplify please.......attached
Setler [38]

Answer:

Exact form: 4 √ 2  +  √ 3

Decimal form: 7.38890505...

6 0
3 years ago
Read 2 more answers
What is the decimal equivalent of the fraction 8/10
morpeh [17]

Answer:

0.8

Step-by-step explanation:

The fraction 8/10 is 0.8 as a decimal because you divide 8 by 10.

5 0
3 years ago
Read 2 more answers
How many solutions does the equation: 4x+2=12x+6 have?
Alchen [17]
1 solution as the highest power on the unkown, x, is 1 so it’s a linear equation this causes it to have only 1 solution
4 0
2 years ago
Write the polynomial as the product of linear factors.<br><br> h(x) = x^2 ? 2x + 10
miss Akunina [59]

Answer:

If h(x) = x^2 + 2x + 10 then (x+1-3i)*(x+1+3i).

If h(x) = x^2 - 2x + 10 then (x-1-3i)*(x-1+3i).

Step-by-step explanation:

In order to write the polynomial as the product of linear factors, we need to find the roots of the polynomial. A quadratic equation is defined as:

ax^2+bx+c

Because the given polynomial expression is a quadratic equation, we can use the following equations for calculating the roots:

x1=(-b/2a)+\sqrt{b^2-4ac}/2a

x1=(-b/2a)-\sqrt{b^2-4ac}/2a

Since the second term sign is not given, then we can write the expression as:

x^2+s2x+10, in which a=1, b=s2 where 's' represents a sign (- or +), and c=10.

Using the equation for finding the roots we obtain:

x1=(-sb/2a)+\sqrt{b^2-4ac}/2a

x1=(-s2/2*1)+\sqrt{2^2-4*1*10}/(2*1); notice that (sb)^{2} = 2^{2}

x1=(-s1)+\sqrt{-36}/2

x1=-(s1)+6i/2

x1=-(s1)+3i

x2=(-sb/2a)-\sqrt{b^2-4ac}/2a

x2=(-s2/2*1)-\sqrt{2^2-4*1*10}/(2*1); notice that (s2)²=2^2

x2=(-s1)-\sqrt{-36}/2

x2=-(s1)-6i/2

x2=-(s1)-3i

If we consider 's' as possitive (+) the roots are:

x1=-1+3i and x2=-1-3i

Whereas if we consider 's' as negative (-) the roots are:

x1=1+3i and x2=1-3i

The above means that if the equation is h(x) = x^2 + 2x + 10, then we can express the polynomial as: (x+1-3i)*(x+1+3i).

But, if the equation is h(x) = x^2 - 2x + 10, then we can express the polynomial as: (x-1-3i)*(x-1+3i).

4 0
3 years ago
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