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Anton [14]
3 years ago
5

You are calculating potential income from an association's request for proposal. The convention will require 200 rooms for three

nights, 3 lunches for 350 people at each lunch, and AV equipment for 10 breakout rooms for three days. Assuming you charge $150 per night per room, $10 per person per lunch, and $300 total per breakout room per day for the A/V equipment, what is your estimated income for the convention?
A)$98,000
B)103,500
C)109,500
D)112,000
Mathematics
1 answer:
Murljashka [212]3 years ago
3 0

Answer:

c

Step-by-step explanation:

step by step my g

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vitfil [10]

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9x5=45

answer: 8/45

6 0
3 years ago
todd Has a collection of 8cds and sally has a collection of 18 cds Todd is adding 9cds a month to his collection while sally is
STatiana [176]

Answer:

Step-by-step explanation:

Let's create some equations first.

Say M = number of months, T = Todd and S = Sally.

We know that Todd starts with 8 cds and sally starts with 18 cds.

This means when M= 0,  T = 8 and S = 18

After one month (M = 1), Todd adds 9 cds.

This means can write the following equation:

T = 8 + 9M

So after the first month (where M = 1), we can find out that Todd has

T = 8 + 9 x 1 = 8 + 9 = 17 cds

For Sally, we know she adds 7 cds per month.

S = 18 + 7M

After one month (M = 1),

S = 18 + 7 x 1 = 25 cds.

Now we are trying to find when they will have the same number of cds and how many.

This means we are trying to figure out what M = ? when Todd and Sally are equal.

So we want to find when T = S

Remember, earlier we wrote :

T = 8 + 9M

S = 18 + 7M

If T = S, this means:

8 + 9M = 18 + 7M

Gather the like terms and solve for M.

Subtract 8 from both sides.

9M = 10 + 7M

Subtract 7M from both sides

2M = 10

Divide both sides by 2

M = 5.

So in 5 months, we are saying T = S (Todd and Sally will have the same number of cds).

Put M = 5 back into our earlier equations to find out how many cds they have after 5 months.

T = 8 + 9M

T = 8 + 9 x 5

T = 53

Therefore, after 5 months Todd and Sally will have 53 cds each :)

6 0
3 years ago
Can you please help me answer this picture​
Nana76 [90]

Answer:

Step-by-step explanation:

b + 2 = b + 2

8 0
3 years ago
Read 2 more answers
If k‐th term of a sequence is ak = ( -1) ^k(2-k)k/2k-1
max2010maxim [7]

Given:

kth term of a sequence is

a_k=\dfrac{(-1)^k(2-k)k}{2k-1}

To find:

The next term a_{k+1} when k is even.

Solution:

We have,

a_k=\dfrac{(-1)^k(2-k)k}{2k-1}

Put k=k+1, to get the next term.

a_{k+1}=\dfrac{(-1)^{k+1}(2-(k+1))(k+1)}{2(k+1)-1}

If k is even, then k+1 must be odd and odd power of -1 gives -1.

a_{k+1}=\dfrac{(-1)(2-k-1)(k+1)}{2k+2-1}

a_{k+1}=\dfrac{(-1)(1-k)(1+k)}{2k+1}

a_{k+1}=-\dfrac{1^2-k^2}{2k+1}    [\because (a-b)(a+b)=a^2-b^2]

a_{k+1}=-\dfrac{1-k^2}{2k+1}

Therefore, the next term is a_{k+1}=-\dfrac{1-k^2}{2k+1}.

7 0
3 years ago
Estimate the sum.<br><br> 10 1/9 + 5 14/15
Ede4ka [16]
The answer is 16 6/135
7 0
3 years ago
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