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Alex17521 [72]
3 years ago
10

PLEASE HELPPPPPPPPPPPP

Chemistry
2 answers:
Blizzard [7]3 years ago
6 0

Answer:

lol good luck

Explanation:

ki77a [65]3 years ago
4 0

Answer:

375.15

Explanation:

i used a calculator. hope it helped  8)

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Natasha_Volkova [10]

Answer:

I dont know sorry i will try my best htough

Explanation:

7 0
2 years ago
A 2. 75-l container filled with co2 gas at 25°c and 225 kpa pressure springs a leak. When the container is re-sealed, the pressu
Serjik [45]

The number of moles of gas lost is  0.0213 mol. It can be solved with the help of Ideal gas law.

<h3>What is Ideal law ?</h3>

According to this law, "the volume of a given amount of gas is directly proportional to the number on moles of gas, directly proportional to the temperature and inversely proportional to the pressure. i.e.

PV = nRT.

Where,

  • p = pressure
  • V = volume (1.75 L = 1.75 x 10⁻³ m³)
  • T =  absolute temperature
  • n = number of moles
  • R =  gas constant, 8.314 J*(mol-K)

Therefore, the number of moles is

n = PV / RT

State 1 :

  • T₁ = (25⁰ C = 25+273 = 298 K)
  • p₁ = 225 kPa = 225 x 10³ N/m²

State 2 :

  • T₂ = 10 C = 283 K
  • p₂ = 185 kPa = 185 x 10³ N/m²

The loss in moles of gas from state 1 to state 2 is

Δn = V/R (P₁/T₁ - P₂/T₂ )

V/R = (1.75 x 10⁻³ m³)/(8.314 (N-m)/(mol-K) = 2.1049 x 10⁻⁴ (mol-m²-K)/N

p₁/T₁ = (225 x 10³)/298 = 755.0336 N/(m²-K)

p₂/T₂ = (185 x 10³)/283 = 653.7102 N/(m²-K)

Therefore,

Δn = (2.1049 x 10⁻⁴ (mol-m²-K)/N)*(755.0336 - 653.7102 N/(m²-K))

    = 0.0213 mol

Hence, The number of moles of gas lost is 0.0213 mol.

Learn more about ideal gas here ;

https://brainly.in/question/641453

#SPJ1

3 0
2 years ago
When hydrogen chloride (HCI) reacts with ammonia (NH3), ammonium chloride (NH4CI) is
givi [52]

Answer:

AMEN NNNNNNNNNNNNNNNNNNNNNNNN

6 0
3 years ago
Would you see more living things in a Biome or an Ecosystem?
kicyunya [14]

Answer:

A Biome is way bigger than a ecosystem

Explanation:

5 0
3 years ago
Read 2 more answers
A gas has a pressure of 0.470 atm at 60.0 C. What is the pressure at standard temperature?
OLEGan [10]

Answer:

P2=0.385atm

Explanation:

step one:

Given that the temperature T1=  60 Celcius

we can convert this to kelvin by adding 273k to 60 Celcius

we have T1= 333k

pressure P1= 0.470 atm

step two:

we know that the standard temperature is T2= 273K

Applying the temperature and pressure relationship we have

P1/T1=P2/T2

substituting our given data we have

0.47/333=P2/273

cross multiply we have

P2= (0.47*273)/333

P2= 128.31/333

P2=0.385 atm

6 0
3 years ago
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