Answer:
The new acceleration becomes twice the pervious acceleration.
Explanation:
Given that,
Mass of the rock, m = 3 kg
Force, F = 1 N
We know that the force acting on an object is given by :
F = ma
a is acceleration of the rock
Put m = 3 kg and F = 1N,
If the force is doubled, F' = 2 N
So,
F'=ma'
So, the new acceleration becomes twice the initial acceleration.
Answer:
Q = 0.50
No
Left
Explanation:
At a generic reversible equation
aA + bB ⇄ cC + dD
The reaction coefficient (Q) is the ratio of the substances concentrations:
Solids and liquid water are not considered in this calculus.
When the reaction achieves equilibrium (concentrations are constant), the Q value is named as Kc, which is the equilibrium constant of the reaction. If Q > Kc, it indicates that the concentration of the products is higher, so, the reaction must progress to the left and form more reactants; if Q < Kc, than the concentrations of the reactants, are higher, so, the reaction progress to the right.
In this case:
Q =
Q = 0.50
So, Q > Kc, the reaction is not at equilibrium and it progresses to the left.