Answer:
Explanation:
101 dB = 10.1 B.
Maximum intensity of sound allowed = 10.1 B
Intensity of sound in terms of W/m² can be found as follows
log (I / I₀) = 10.1
I / I₀ = 10¹⁰°¹
I = I₀ X 10¹⁰°¹
= 10⁻¹² X 10¹⁰°¹
= 10⁻¹°⁹ W/m²
105 m above the ground the this intensity will be 105² times
intensity at source point = 10⁻¹°⁹ x 105²
= 138.79 W/m²
energy of sound from source
= 4π times
= 4 x 3.14 x 138.79
= 1743.28W/m²
To calculate in terms of decibel :
log 1743.28 / 10⁻¹²
= log 1743.28 +12
= 15.24 B
= 152.4 dB .
152.4 dB .
Spring C stretches 100 cm.
Explanation:
The spring constant is simply the stiffness of the spring. The higher the spring constant the more stiff the spring is.
Spring constant shows the force needed to stretch a spring from it's equilibrium position. If a material requires more force to cause it to stretch, it will have a high spring constant.
According to hooke's law "the force needed to extended an elastic material is directly proportional to its extension"
F = ke
k is the spring constant
e is the extension
We see that the spring that stretches by 100 is the less stiff compared to other springs. It has the smallest spring constant.
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Answer:
The portfolio should invest 48.94% in equity while 51.05% in the T-bills.
Explanation:
As the complete question is not given here ,the table of data is missing which is as attached herewith.
From the maximized equation of the utility function it is evident that
For the equity, here as
is percentage of the equity which is to be calculated
is the Risk premium whose value as seen from the attached data for the period 1926-2015 is 8.30%
is the risk aversion factor which is given as 4.
is the standard deviation of the portfolio which from the data for the period 1926-2015 is 20.59
By substituting values.
So the weight of equity is 48.94%.
Now the weight of T bills is given as
So the weight of T-bills is 51.05%.
The portfolio should invest 48.94% in equity while 51.05% in the T-bills.
4. a poor insulator
If rest other things are kept constant or unchanged then a good conductor can be termed as a poor insulator.
