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docker41 [41]
3 years ago
6

According to its periodic table entry, how many electrons does nickel have in its valence level?

Physics
2 answers:
steposvetlana [31]3 years ago
5 0

2 valence electrons

Explanation:

Electron configuration of nickel (Ni):

1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁸

The valence electrons are in the electronic shell with the higher principal quantum number (n). In our case, nickel have 2 electrons in the 4s², with the n = 4.

Learn more about:

electrons in the valence level

brainly.com/question/5523364

brainly.com/question/8320786

#learnwithBrainly

Anna11 [10]3 years ago
4 0

Answer:

Nickel has 2 electrons in its valence level.

Explanation:

The Electronic Configuration of the elements is the arrangement of all electrons of an element in energy levels and sub-levels (orbitals).

There are 7 energy levels, numbered from 1 to 7. Each level is divided into sub-levels. These sub-levels into which each level is divided can be up to 4. These 4 sub-levels are called: s, p, d, f.

According to the periodic table entry, you can see that the nickel has an electronic configuration of [Ar] 3d⁸ 4s²

The number that precedes the representative letter of each orbital or sub-level indicates the level of energy where the electron is located, the letter indicates the type of orbital or sub-level where the electron is located and the exponent indicates the number of electrons found in the orbital.

Note that Ar is the noble gas of the previous period. In square brackets, as shown in the case of nickel, indicates the internal electronic structure of the element. So the electronic configuration of the nickel is:

1s² 2s² 2 p⁶ 3s² 3p⁶ 3d⁸ 4s²

Valencia electrons are the electrons found in the last electronic layer (called valence orbitals).  The last electronic layer is the layer furthest from the nucleus, which in this case can be seen to be the electronic layer or level 4.  At this level you can see the letter s, which, as mentioned, indicates the type of orbital where the electrons are located, and the exponent 2, which indicates the number of electrons found in said orbital.

So, <u><em>nickel has 2 electrons in its valence level.</em></u>

<u><em></em></u>

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Answer:

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Explanation:

For this exercise we use that the work done by the friction force plus the potential energy equals the change in the body's energy.

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        N - W_y = 0

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X axis

        Wₓ - fr = ma

let's use trigonometry

        sin  θ = y / L

         sin θ = 11/110 = 0.1

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         sin 5.74 = Wₓ / W

         cos 5.74 = W_y / W

         Wₓ = W sin 5.74

         W_y = W cos 5.74

the formula for the friction force is

         fr = μ N

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Work is friction force is

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Let's use the relationship of work with energy

        W + ΔU = ΔK

         -μ mg L cos 5.74 + (mgh - 0) = 0  - ½ m v²

        v² = - 2 μ g L cos 5.74 +2 (gh)

        v² = 2gh - 2 μ gL cos 5.74

let's calculate

        v² = 2 9.8 11 - 2 0.07 9.8 110 cos 5.74

        v² = 215.6 -150.16

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A resonant circuit using a 286-nFnF capacitor is to resonate at 18.0 kHzkHz. The air-core inductor is to be a solenoid with clos
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Answer:

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From the question we are told that

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      The resonance frequency is  f = 18.0 kHz =  18*10^{3} Hz

       The diameter is  d =  1.1 mm = \frac{1.1 }{1000} = 0.00011 \ m

       The  of the air-core inductor is l = 12 \ m

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Generally the inductance of this air-core inductor is mathematically represented as

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making N the subject of  the formula

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              N =  \frac{1}{2 \pi f} * \frac{2}{d} * \sqrt{\frac{l}{\pi * \mu_o * C} }

             

 Substituting value

            N =  \frac{1}{ 3.142  * 18*10^{3} * 0.00011 }  \sqrt{\frac{12}{ 3.142  * 4 \pi *10^{-7}* 286 *10^{-9}} }

              N = 523962.32 loops  

4 0
2 years ago
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