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GaryK [48]
3 years ago
5

Find [4(cos15° + isin15°)]^3 and express it in a + bi form.

Mathematics
1 answer:
arsen [322]3 years ago
3 0

Answer:

see explanation

Step-by-step explanation:

Using De Moivre's theorem

Given

[ 4(cos15° + isin15° ) ]³, then

= 4³ [ cos(3 × 15°) + isin(3 × 15°) ]

= 64 (cos45° + isin45° )

= 64 (\frac{\sqrt{2} }{2} + \frac{\sqrt{2} }{2} i )

= 64 (\frac{\sqrt{2} }{2} (1 + i) )

= 32\sqrt{2} (1 + i)

= 32\sqrt{2} + 32\sqrt{2} i

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