Find [4(cos15° + isin15°)]^3 and express it in a + bi form.
1 answer:
Answer:
see explanation
Step-by-step explanation:
Using De Moivre's theorem
Given
[ 4(cos15° + isin15° ) ]³, then
= 4³ [ cos(3 × 15°) + isin(3 × 15°) ]
= 64 (cos45° + isin45° )
= 64 (
+
i )
= 64 (
(1 + i) )
= 32
(1 + i)
= 32
+ 32
i
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