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GaryK [48]
3 years ago
5

Find [4(cos15° + isin15°)]^3 and express it in a + bi form.

Mathematics
1 answer:
arsen [322]3 years ago
3 0

Answer:

see explanation

Step-by-step explanation:

Using De Moivre's theorem

Given

[ 4(cos15° + isin15° ) ]³, then

= 4³ [ cos(3 × 15°) + isin(3 × 15°) ]

= 64 (cos45° + isin45° )

= 64 (\frac{\sqrt{2} }{2} + \frac{\sqrt{2} }{2} i )

= 64 (\frac{\sqrt{2} }{2} (1 + i) )

= 32\sqrt{2} (1 + i)

= 32\sqrt{2} + 32\sqrt{2} i

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3 years ago
If one of the zeros of the cubic polynomial x3 + ax2 + bx + c is -1, then what will be the product of the other two zeros?
zhenek [66]

Answer:

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Step-by-step explanation:

Let α, β and γ be the zeros of the polynomial x³ + ax² + bx + c. Since one of the zeros is -1, therefore let γ = -1. Hence:

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