The female part of the chromosomes, usually colored pink in diagrams
Answer:
54 days
Explanation:
We have to use the formula;
0.693/t1/2 =2.303/t log Ao/A
Where;
t1/2= half-life of phosphorus-32= 14.3 days
t= time taken for the activity to fall to 7.34% of its original value
Ao=initial activity of phosphorus-32
A= activity of phosphorus-32 after a time t
Note that;
A=0.0734Ao (the activity of the sample decreased to 7.34% of the activity of the original sample)
Substituting values;
0.693/14.3 = 2.303/t log Ao/0.0734Ao
0.693/14.3 = 2.303/t log 1/0.0734
0.693/14.3 = 2.6/t
0.048=2.6/t
t= 2.6/0.048
t= 54 days
Answer:
Approximately
.
Explanation:
Look up the specific heat of gaseous neon:
.
Calculate the required temperature change:
.
Let
denote the mass of a sample of specific heat
. Energy required to raise the temperature of this sample by
:
.
For the neon gas in this question:
Calculate the energy associated with this temperature change:
.
Answer:
True
Explanation:
Atmospheric pressure reduces the amount of oxygen in the air, therefore leading to Hypoxia. Higher altitues contribute.