Given :
Molarity of acetic acid solution, M = 0.10 M.
pKa of acetic acid, pKa = 4.75 .
To Find :
Percentage dissociation of 0.10 M solution of acetic acid.
Solution :
We know, 
Taking antilog both side, we get :
Since, acetic acid has 1 hydrogen atom to loose , so it is a monoprotic acid.
Now, percentage dissociation of monoprotic acid is given by :
Hence, this is the required solution.
Answer:
Because one calorie is equal to 4.18 J, it takes 4.18 J to raise the temperature of one gram of water by 1°C. In joules, water's specific heat is 4.18 J per gram per °C. If you look at the specific heat graph shown below, you will see that 4.18 is an unusually large value.
Answer:
Heat is the transfer of energy. During energy transfer, the energy moves from the hotter object to the colder object. This means that the hotter object will cool down and the colder object will warm up. The energy transfer will continue until both objects are at the same temperature.
Explanation:
The molarity of the solution will be 4.97 M.
<h3>What is molarity?</h3>
It is the number of moles of solutes per 1 liter of solvent or solution.
Mole of 34.1 g NaCl = 34.1/58.44 = 0.5835 mol
117.3 mL = 117.3/1000 = 0.1173 L
Molarity of the solution = 0.5835/0.1173 = 4.97 M
More on molarity can be found here: brainly.com/question/2817451
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