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vazorg [7]
2 years ago
5

There are two suspects in a shooting investigation. Bullets are recovered from the crime scene. Both suspects own guns, and thes

e guns have been seized by the police. How will the investigators check to see if one of these guns fired the found bullets?
Chemistry
1 answer:
Gwar [14]2 years ago
7 0

Answer:

They can check if one of the bullets is gone if the gun was fully loaded or they can see if there is any particles of gun powder on the gun. I may be wrong.

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Why are the alkali metals and the halogens very reactive
jeyben [28]

Answer:

Answer in explanation

Explanation:

The reactivity or passiveness of an element depends solely on how close it is to attain a noble gas configuration. This means the closer an element is to attain a noble gas configuration, the greater its reactivity in both direction, positively or negatively.

Alkali metals belong to group 1 of the periodic table while halogens belong to group 17 of the periodic table. This means they are just one electron away from achieving the stability of a noble gas configuration. While alkali metals need to lose one electron to form a univalent positive ion, halogens news to gain one electron to form a univalent negative ion.

They tend to go about this vigorously and as such undergo several chemical reactions because of that single electron they neeed.

4 0
2 years ago
Which statement compares the attractive forces that hold particles together?
olga nikolaevna [1]

Answer:

These are examples of INTERmolecular attractions (the other three are examples of INTRAmolecular bonds).

Explanation:

4 0
3 years ago
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Which of the following organism are most likely to show cospeciation?
Viktor [21]
The answer is A: fleas and cats.
3 0
3 years ago
What have all living things evolved from?
dedylja [7]
Earlier species thanks to evolution. hope this helped!

3 0
3 years ago
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How many grams of water at 50◦c must be added to 16 grams of ice at −12◦c to result in only liquid water at 0◦c?
melisa1 [442]

When water at 50 C is added to ice at -12 C, heat is transferred from hot water to ice.

- Heat given out by water = Heat absorbed by ice

Calculating the heat released by hot water:

q = m CwaterΔTq = m (4.184\frac{J}{(g.^{0}C)} )(0^{0}C-50^{0}C)

Calculating heat absorbed by 16 g of ice: Ice at -12^{0}C is converted to ice at O^{0}C and then ice at O^{0} C to water at 0^{0}C

q = m CiceΔT + m (Heat of fusion)

q = 16 g(2.11\frac{J}{g.^{0}C})(0^{0}C - (-12^{0}C)) + 16 g (333.55\frac{J}{g})

q = 405.12 J +5336.8 J =5741.92 J

- Heat given out by water = Heat absorbed by ice

-(m(4.184\frac{J}{g.^{0}C})(0^{0}C-50^{0}C) = 5741.92 J

m = 27.4 g

Therefore, 27.4 g water at 50^{0}C must be added to 16 g of ice at -12^{0}C to convert to liquid water at 0^{0}C

4 0
3 years ago
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