It has 6 electrons, and 4 valence electrons
The mass of sodium chloride at the two parts are mathematically given as
- m=10,688.18g
- mass of Nacl(m)=39.15g
<h3>What is the mass of sodium chloride that can react with the same volume of fluorine gas at STP?</h3>
Generally, the equation for ideal gas is mathematically given as
PV=nRT
Where the chemical equation is
F2 + 2NaCl → Cl2 + 2NaF
Therefore
1.50x15=m/M *(1.50*0.0821)
1-50 x 15=m/58.5 *(1.50*0.0821)
m=10,688.18g
Part 2
PV=m'/MRT
1*15=m'/58.5*0.0821*273
m'=39.15g
mass of Nacl(m)=m'=39.15g
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Answer: short answer short 0.65 / 5.37
15% NaOH by mass is 15g of NaOH in (100-15)g of solution.
No. Of moles of NaOH in solution = 0.65
No of moles of Water in solution = 4.72
Mole Fraction =
(
(Moles of Solvent)
(Moles Of Solute)+(Moles of Solvent)
)
OR
(
(Moles of Solvent)
Total Number Of Moles
)
= 0.65 / 5.37
= 0.121
Explanation:
Hope this helped
