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3 years ago

I need help to solve this please

Mathematics

1 answer:

Effectus [21]3 years ago

8 0

Answer:

hahahaha qiau181e81 8qy28e82

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Which of the following relationships represents a function?

Keith_Richards [23]

A function is a repesentashion of time. past or befor so fg means function grafgh is what your exsplaining as in repacentation of wrk)bg, is what happend befor like 1990 no one knows so I would say D

because 4_4 16 4;3 22 is the closest between function and befor g and after becuse 44_16 is 2004 and 20016 do you see know go hard rock star ;-)

4 0

3 years ago

PLSSSS I NEED HELP ASAPP

LiRa [457]

Answer:

rip

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Use FOIL to explain how to find the product of (a + b)(a − b). Then describe a shortcut that you could use to get this product w

xenn [34]

Answer:

The product of (a+b)(a-b) is $a^2 - b^2$

Step-by-step explanation:

Use FOIL to explain how to find the product of (a + b)(a − b)

FOIL is

Multiply First terms : a*a = a^2

Multiply Outside terms : a* -b = -ab

Multiply Inner terms : b * a= ab

Multiply last terms : b * -b = -b^2

now we combine all the terms

$a^2 -ab+ab - b^2$

combine like terms

$a^2 - b^2$

The product of (a+b)(a-b) is $a^2 - b^2$

Shortcut is we apply an identity

$a^2 - b^2 = (a+b)(a-b)$

8 0

2 years ago

Read 2 more answers

Solve the inequality 2(4x-3)>-3(3)+5x

Sholpan [36]

Answer:

$x > -1\\$

Step by step explanation:

$~~~~~2(4x-3) > -3(3)+5x\\\\\implies 8x-6 > -9+5x\\\\\implies 8x > -9+6+5x\\\\\implies 8x > -3+5x\\\\\implies 8x -5x > -3\\\\\implies 3x > -3\\\\\implies x > -\dfrac 33\\\\\implies x > -1$

5 0

2 years ago

Prove that <br><img src="https://tex.z-dn.net/?f=4cot45%20%5E%7B2%7D%20%20-%203tan%20%5E%7B2%7D%2060%20%2B%202sec%20%5E%7B2%7D60

sesenic [268]

Answer:

$4 \cot {}^{2} (45) - 3 \tan {}^{2} (60) + 2 \sec {}^{2} (60) = 3 \\$

$LHS = 4 \cot {}^{2} (45) - 3 \tan {}^{2} (60) + 2 \sec {}^{2} (60) \\$

let us first take a look at the values of the trigonometric ratios given in the question so that we get quite clear about what is to be done.

here ,

$\cot(45) = 1 \\ \\ \tan(60) = \sqrt{3} \\ \\ \sec(60) = 2$

now ,

we just have to plug in the values considering certain other things given in the question and we're done!

so let's start ~

$4(1) {}^{2} - 3( \sqrt{3} ) {}^{2} + 2(2) {}^{2} \\ \\ \dashrightarrow \: 4(1) - 3(3) + 2(4) \\ \\ \dashrightarrow \: 4 - 9 + 8 \\\\ \dashrightarrow \: 12 - 9 \\ \\\dashrightarrow \: 3 = RHS$

hence , proved ~

hope helpful :D

7 0

2 years ago