A pendulum bob executing simple harmonic motion has 2cm and 12Hz as amplitude and frequency respectively. Calculate the period o
1 answer:
Answer:
Explanation:
The amplitude is extraneous information for this question.
Period (T) is simply a measure of time (how long it takes to complete a full cycle).
The frequency (f), is the reciprocal (how many cycles it can complete per unit of time).
The frequency reported is 12Hz. Hz is a unit meaning "cycles per second"
Thus 12cycles = 1second.
To find the number of seconds per cycle, simply create the other unit fraction and simplify:
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Answer:
Explanation:
Since we know that two sphere is oppositely charged so net electric field at the mid point of two balls will be sum of the electric field due to each ball at the mid point
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here we know that
so we have
Answer:
Check attachment for better understanding
Explanation:
Given that
a= 0.75m
b=1.31m
c= 2.2m
Weight of pole is 26.90
Then, Fg = Weight = 26.90
Using Equilibrium of forces
ΣFy = 0
U — D — Fg = 0
U — D = Fg
U — D = 26.9
To calculate U,
We will take moment about point A.
ΣMa = 0
Let the clockwise moment be positive and anti-clockwise be negative
Fg(a+b) — U(a) = 0
26.9(1.31+0.75) —0.75U = 0
26.9(2.06) = 0.75U
0.75U = 55.414
U = 55.414/0.75
U = 73.89 N
To calculate D,
U — D = 26.9
73.89—D =26.9
73.89—26.9 = D
D = 46.99N
