There are 1000 blank in a meter
1 answer:
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Answer:
The recoil velocity of the projectile is 0.0025m/s
Explanation:
Given:
Mass of the projectile =0.005kg
Mass of the launcher = 1500kg
Velocity = 750 m/s.
To Find:
The recoil velocity of the projectile = ?
Solution:
The recoil velocity is the obtained by dividing the "recoil momentum" by the "mass of the recoil body". The recoil momentum is equal to the momentum of the other body. The momentum of the other body is equal to it mass times its velocity.
Lets find the recoil momentum,
Recoil momentum = mass of the projectile X velocity
Recoil momentum =
Recoil momentum = 3.75
Now Recoil Velocity,
Recoil Velocity =
Recoil Velocity =
Recoil Velocity = 0.0025m/s
Answer:
E = 4.75 x 10⁻¹⁶ J
Explanation:
given,
wavelength of the x-ray , λ = 4.18 Å
Energy of photon = ?
we know
where h is the planks constant
c is the speed of light
h = 6.626 x 10⁻³⁴ m² kg / s
c = 3 x 10⁸ m/s
now,
E = 4.75 x 10⁻¹⁶ J
hence, the energy of the photon is equal to E = 4.75 x 10⁻¹⁶ J
Answer:
The response to this question is as follows:
Explanation:
The whole question and answer can be identified in the file attached, please find it.
Answer:
Explanation:
The final answer is
