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abruzzese [7]
2 years ago
14

The main reason that rods are more sensitive to light than cones is that

Physics
1 answer:
Mamont248 [21]2 years ago
3 0
B. Is the answer explanation: if not you need help me or you can sleep over here every day so that you don’t know where you can
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when the armature of an ac generatr rotates at 15.0 rad/s, the amplitude of the induced emf is 27.0 V. What is the amplitude of
nata0808 [166]

To solve this problem we will apply the concepts related to the electric field. This is defined as the product between the angular frequency, the number of turns of the body (solenoid in this case) the magnetic field and the sine of the angular frequency and time. Mathematically this can be described as

E = \omega NBA |sin \omega t|

Here,

\omega = Angular frequency

N = Number of turns

B = Magnetic field

The emf has its maximum value when sin \omega t = \pm 1

Thus the amplitude of the emf is

E = \omega NBA

When number of turns of armature, area and applied magnetic field remains constant, induced emf is proportional to angular speed.

E \propto \omega

Further it can be written as follows,

\frac{E_1}{E_2} \propto \frac{\omega_1}{\omega_2}

E_2 = \frac{\omega_2}{\omega_1}E_1

E_2 = \frac{10rad/s}{15rad/s}(27.0V)

E_2 = 18V

Therefore the maximum amplitude of induced emf when armature rotates at 10.0rad/s is 18V

5 0
3 years ago
Can you access an instance variable from a static method? explain why or why not.
marusya05 [52]
<span>The reason a static method can't access instance variable is because static references the class not a specific instance of the class so there is no instance variable to access.</span>
5 0
4 years ago
if the mass of the marble is 0.025kg, and you assume that on the first drop of your roller coaster (height=8cm) the marble is fa
Nookie1986 [14]

1. What is the force of the marble?

For an object near the surface of the earth, the gravitational force acting upon the object is given by:

F = mg

F is the gravitational force, m is the object's mass, and g is the acceleration of objects due to earth's gravity.

Given values:

m = 0.025kg, g = 9.8m/s²

Plug in the given values and solve for F:

F = 0.025×9.8

F = 0.25N

2. What is the marble's potential energy at the start of its fall?

The gravitational potential energy of an object near the earth's surface is given by:

PE = mgh

PE is the potential energy, m is the object's mass, g is the acceleration of objects due to earth's gravity, and h is the object's relative height.

new given values:

h = 0.08m

Since F = mg, you can simply multiply F×h to get PE. Use the result from question 1:

PE = F×h

PE = 0.25×0.08

PE = 0.02J

4 0
3 years ago
Starting from rest, a runner at a track meet reaches a speed of 7.5 m/s in 1.7 s. How far does she run during this time, assumin
Alex17521 [72]
For this problem, we use the equations derived for rectilinear motion at constant acceleration. The equations are:

a = (v - v₀)/t
x = v₀t + 0.5at²
where
a is acceleration
v and v₀ are the final and initial velocities, respectively
x is the distance
t is the time

First, let's determine the a to be used in the second equation:

a = (7.5 m/s - 0 m/s)/1.7 s = 4.411 m/s²
x = (0)(1.7s) + 0.5(4.411 m/s²)(1.7 s)²
x = 6.375 m
7 0
3 years ago
Which tool would you use to measure the amount of rainfall?
zheka24 [161]

Answer:

a

Explanation:

5 0
3 years ago
Read 2 more answers
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