All categories

3 years ago

Find the distance between the point - 3, 2 and 1 - 1

Mathematics

1 answer:

dusya [7]3 years ago

7 0

Answer:

5 units

Step-by-step explanation:

Find the distance between the point - 3, 2 and 1 - 1

Given data

x1= -3

y1= 2

x2= 1

y2= -1

The expression for the distance between two points is

d=√((x_2-x_1)²+(y_2-y_1)²)

subtitute

d=√((1-(-3))²+(-1-(2))²)

d=√((1+3))²+(-1-2))²)

d=√((4)²+(-3))²)

d=√16+9

d=√25

d=5

Hence the distance between the points is 5 units

You might be interested in

The measure of one acute angle in this right triangle is 30°. What is the measure of the

Viktor [21]

Answer:

60°

..................

8 0

3 years ago

Read 2 more answers

Simplify √(49^8) ? a) 7√(5a^8) b) 7a^4 c)a√(24.5) d) 7a^8 please help as soon as possible.

WITCHER [35]

$\bf \sqrt{49^8}~~
\begin{cases}
49=7\cdot 7\\
\qquad 7^2
\end{cases}\implies \sqrt{(7^2)^8}\implies \sqrt{(7^8)^2}\implies 7^8\\\\\\ 5764801$

5 0

3 years ago

The two rectangular prisms are similar.

Sophie [7]

Answer:

The volume of the larger rectangular prism is $648\ cm^{3}$

Step-by-step explanation:

we know that

If two figures are similar, then the ratio of its volumes is equal to the scale factor elevated to the cube

Let

z-----> the scale factor

x-----> the volume of the larger rectangular prism

y-----> the volume of the smaller rectangular prism

$z^{3}=\frac{x}{y}$

In this problem we have

$z=\frac{12}{4}=3$ ---> the scale factor is equal to the ratio of its corresponding sides

$y=24\ cm^{3}$

substitute and solve for x

$3^{3}=\frac{x}{24}$

$x=27*24=648\ cm^{3}$

6 0

3 years ago

Drag each number to the correct location on the table. Each number can be used more than once, but not all numbers will be used.

muminat

Answer:

1. $12x^2-13.4x-11$

- Degree: 2

- Number of terms: 3

2. $7x^3+168$

- Degree: 3

- Number of terms: 2

3. $9x^4-9$

- Degree: 4

- Number of terms: 2

Step-by-step explanation:

For this exercise you need to remember the multiplication of signs:

$(+)(+)=+\\(-)(-)=+\\(-)(+)=-\\(+)(-)=-$

1. Given:

$(4x + 2.2)(3x - 5)$

Apply the Distributive property:

$=12x^2+6.6x-20x-11$

Add the like terms:

$=12x^2-13.4x-11$

You can idenfity that:

- Degree: 2

- Number of terms: 3

2. Given:

$(-304 +503 - 12) + (7x^3 - 25 + 6)$

Add the like terms:

$=187 + 7x^3 - 25 + 6=7x^3+168$

You can idenfity that:

- Degree: 3

- Number of terms: 2

3. Given:

$(3x^2 - 3)(3x^2 + 3)$

Apply Distributive property:

$=9x^4-9x^2+9x^2-9$

Add the like terms:

$=9x^4-9$

You can idenfity that:

- Degree: 4

- Number of terms: 2

8 0

3 years ago

Domain and Range for the function f(x)=5IXI is

shutvik [7]

Answer:

The domain of the function f(x) is:

$\mathrm{Domain\:of\:}\:5\left|x\right|\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:$

The range of the function f(x) is:

$\mathrm{Range\:of\:}5\left|x\right|:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\ge \:0\:\\ \:\mathrm{Interval\:Notation:}&\:[0,\:\infty \:)\end{bmatrix}$

Step-by-step explanation:

Given the function

$f\left(x\right)=5\left|x\right|$

Determining the domain:

We know that the domain of the function is the set of input or arguments for which the function is real and defined.

In other words,

Domain refers to all the possible sets of input values on the x-axis.

It is clear that the function has undefined points nor domain constraints.

Thus, the domain of the function f(x) is:

$\mathrm{Domain\:of\:}\:5\left|x\right|\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:$

Determining the range:

We also know that range is the set of values of the dependent variable for which a function is defined.

In other words,

Range refers to all the possible sets of output values on the y-axis.

We know that the range of an Absolute function is of the form

$c|ax+b|+k\:\mathrm{is}\:\:f\left(x\right)\ge \:k$

$k=0$

Thus, the range of the function f(x) is:

$\mathrm{Range\:of\:}5\left|x\right|:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\ge \:0\:\\ \:\mathrm{Interval\:Notation:}&\:[0,\:\infty \:)\end{bmatrix}$

7 0

3 years ago

Find the distance between the point - 3, 2 and 1 - 1​

Find the distance between the point - 3, 2 and 1 - 1