Answer:
first answer is correct
Step-by-step explanation:
Hello, we want to write 2 + 4 + 6 + ... + 20
for n = 1, 2n = 2*1 =2
for n = 2, 2n = 2*2=4
for n = 3, 2n=2*3=6
etc
so
thanks
Answer:
4
Step-by-step explanation:
Given:
A, B, C, D have distinct positive values for mod 6
A (mod 6) = 1
B (mod 6) = 2
C (mod 6) = 4
D (mod 6) = 5
Each mod 6 value cannot be a zero since the product ABCD is not a multiple of 6.
Furthermore, in order that ABCD mod 6 > 0, we cannot have a residue equal to 3, else the product with a residue 2 or 4 will make the product a multiple of 6.
Thus the only positive residues can only be 1,2,4,5
A*B*C*D (mod 6) > 0 = 1*2*4*5 (mod 6) = 4
Answer:
300
Step-by-step explanation:
30 * 10 = 300
you can answer it six point six six six six six infinity or you can answer it 6.7 depending upon how they want
4g and 6b and that's a total of 10 in all so you know it will be 1/2 if its going to be two out of two
