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elena-14-01-66 [18.8K]
3 years ago
5

I do not get this pls answer

Mathematics
1 answer:
soldi70 [24.7K]3 years ago
3 0

Answer:

the answer is 83/13 and its simplification is shown in the picture. 6(5/13)

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A random variableX= {0, 1, 2, 3, ...} has cumulative distribution function.a) Calculate the probability that 3 ≤X≤ 5.b) Find the
olchik [2.2K]

Answer:

a) P ( 3 ≤X≤ 5 ) = 0.02619

b) E(X) = 1

Step-by-step explanation:

Given:

- The CDF of a random variable X = { 0 , 1 , 2 , 3 , .... } is given as:

                    F(X) = P ( X =< x) = 1 - \frac{1}{(x+1)*(x+2)}

Find:

a.Calculate the probability that 3 ≤X≤ 5

b) Find the expected value of X, E(X), using the fact that. (Hint: You will have to evaluate an infinite sum, but that will be easy to do if you notice that

Solution:

- The CDF gives the probability of (X < x) for any value of x. So to compute the P (  3 ≤X≤ 5 ) we will set the limits.

                   F(X) = P ( 3=

- The Expected Value can be determined by sum to infinity of CDF:

                   E(X) = Σ ( 1 - F(X) )

                   E(X) = \frac{1}{(x+1)*(x+2)} = \frac{1}{(x+1)} - \frac{1}{(x+2)} \\\\= \frac{1}{(1)} - \frac{1}{(2)}\\\\= \frac{1}{(2)} - \frac{1}{(3)} \\\\=  \frac{1}{(3)} - \frac{1}{(4)}\\\\= ............................................\\\\=  \frac{1}{(n)} - \frac{1}{(n+1)}\\\\=  \frac{1}{(n+1)} - \frac{1}{(n+ 2)}

                   E(X) = Limit n->∞ [1 - 1 / ( n + 2 ) ]  

                   E(X) = 1

8 0
2 years ago
So the question on the pic
gtnhenbr [62]

Explanation + answers

Because there are lengths going from 0 to 1, the lines must mean either decimals or fractions (we'll use fractions for this.)

1. There are twelve lines from 0 and 1, which we can use as the denominator for our fraction. This means the length of each line is 1/12.

2. In order to find where K's point is at, we simply need to count until we get to it. After counting, I see that K is on point 8/12, which we can simplify to get a smaller number. If we simplify once, we get 4/6, which we can again simplify to get 2/3. This gives us the answer K is on point 8/12 or 2/3.

4 0
3 years ago
I don’t 100% remember how to turn this into a standard problem.. could someone help me really quick?
marin [14]
Standard form is ax^2+bx+c=0

First evaluate the exponent and expand (foil).
y= 3(x^2-4x+4)+1

Then distribute the 3
y= 3x^2-12x+12+1

Combine like terms
y=3x^2-12x+13

Final answer: 3x^2-12x+13=0
6 0
3 years ago
Grace swam 0.6 kilometers during her first week of training and 0.25 kilometers during her second week of training. How many kil
mr_godi [17]

Answer:

she will cover a distance of 0.85 km.

Step-by-step explanation:

We have,

Grace swam 0.6 kilometres during her first week of training and 0.25 kilometres during her second week of training.

It is required to find total distance covered by her in all.

It can be calculated simply adding the distance covered in first and second week of training. So,

Total distance, D = 0.6 km +0.25 km = 0.85 km

Hence, she will cover a distance of 0.85 km.

3 0
3 years ago
A biology class conducts a bird count every week during the semester. Using the number of species counted each​ week, a student
luda_lava [24]

Answer:

A student finds a​ 95% confidence interval of​ (16.34,18.69) for the mean number of species counted. This is a valid interval because the mean number of species or any population mean does not necessarily have to be a whole number, as stated by the student.

This given confidence interval of (16.34,18.69) helps us to simply estimate the mean species counted.

4 0
2 years ago
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