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Rzqust [24]
3 years ago
12

Cars are responsible for ____% of CO2 emissions. a10% b25% c100% d0%

Chemistry
1 answer:
Pavlova-9 [17]3 years ago
5 0

Answer:

Explanation:

25%

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What do the properties of waves moving through aquatic environments tell us about the organisms living in those environments?
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3 years ago
A radioactive element reduces to 5.00% of its initial mass in
Stolb23 [73]

The half-life in months of a radioactive element that reduce to 5.00% of its initial mass in 500.0 years is approximately 1389 months

To solve this question, we'll begin by calculating the number of half-lives that has elapsed. This can be obtained as follow:

Amount remaining (N) = 5%

Original amount (N₀) = 100%

<h3>Number of half-lives (n) =?</h3>

N₀ × 2ⁿ = N  

5 × 2ⁿ = 100

2ⁿ = 100/5

2ⁿ = 20

Take the log of both side

Log 2ⁿ = log 20

nlog 2 = log 20

Divide both side by log 2

n = log 20 / log 2

<h3>n = 4.32</h3>

Thus, 4.32 half-lives gas elapsed.

Finally, we shall determine the half-life of the element. This can be obtained as follow.

Number of half-lives (n) = 4.32

Time (t) = 500 years

<h3>Half-life (t½) =? </h3>

t½ = t / n

t½ = 500 / 4.32

t½ = 115.74 years

Multiply by 12 to express in months

t½ = 115.74 × 12

<h3>t½ ≈ 1389 months </h3>

Therefore, the half-life of the radioactive element in months is approximately 1389 months

Learn more: brainly.com/question/24868345

8 0
3 years ago
Planning for the possibility that the plumbing in your house needs repair is part of a plan for _____.
Vera_Pavlovna [14]

Answer:

planning for the possibility that the pluming in your house needs repair is part of <u><em>managing liquidity</em></u>

Explanation:

100 on edginuity

4 0
3 years ago
Read 2 more answers
What is the reasoning for the location of sodium in the periodic table
tatyana61 [14]
Due to it's electronic configuration w/c is 1s2 2s2 2ps 3s1 considering the last w/c is  3s1, sodium should be in row 3 period a1.
3 0
3 years ago
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A 4.0 g sample of a solid changes from 20.0 ºC to 36.0 ºC upon addition of 25.0 cal of heat. What is the specific heat of this s
Grace [21]

Answer: c = 0.39 cal/g°C or

1.63 J/g°C

Explanation: To find the specific heat of the metal we will use the formula of heat which is Q= mc∆T.

We will derive for c, c = Q / m∆T

25.0 cal/ 4.0 g ( 36°C - 20°C)

= 0.39 cal / g°C

Or we can convert calories to joules.

0.39 cal x 4.184 J/ 1 cal

= 1.63 J /g°C

8 0
3 years ago
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