The volume of the cone that has a radius of 8 in. and a height of 10.5 in. is: 703.7 in.³
<h3>What is the Volume of a Cone?</h3>
Volume = 1/3πr²h
Given the parameters:
- Height (h) = 10.5 in.
- Radius (r) = 8 in.
Volume of the cone = 1/3πr²h = 1/3π(8²)(10.5)
Volume of the cone = 1/3π(64)(10.5)
Volume of the cone = 703.7 in.³
Learn more about volume of a cone on:
brainly.com/question/13677400
#SPJ1
Answer:
y=5x−z
Step-by-step explanation:
Step 1: Multiply both sides by y.
xy−5=yz
Step 2: Add -yz to both sides.
xy−5+−yz=yz+−yz
xy−yz−5=0
Step 3: Add 5 to both sides.
xy−yz−5+5=0+5
xy−yz=5
Step 4: Factor out variable y.
y(x−z)=5
Step 5: Divide both sides by x-z.
y(x−z)x−z=5x−z
y=5x−z
<h3><u>The value of x is equal to -2.</u></h3>
5(2x + 8) = -8x + 4
<em><u>Distributive property.</u></em>
10x + 40 = -8x + 4
<em><u>Add 8x to both sides.</u></em>
18x + 40 = 4
<em><u>Subtract 40 from both sides.</u></em>
18x = -36
<em><u>Divide both sides by 18</u></em>
x = -2
A
using the Cosine rule in ΔSTU
let t = SU, s = TU and u = ST, then
t² = u² + s² - (2us cos T )
substitute the appropriate values into the formula
t² = 5² + 9² - (2 × 5 × 9 × cos68° )
= 25 + 81 - 90cos68°
= 106 - 33.71 = 72.29
⇒ t =
≈ 8.5 in → A