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Luba_88 [7]
3 years ago
6

Guided Practice

Mathematics
2 answers:
oksian1 [2.3K]3 years ago
7 0

Answer:  

A.

an=100 · (0.64)n−1a subscript n baseline equals 100 times left parenthesis 0.64 right parenthesis superscript n minus 1 baseline; about 10.74 cm

Step-by-step explanation:  I got it off of the internet

Step 1 of 1

In geometric sequence, the ratio between two consecutive terms is constant. This ration is called the common ratio.

Consider the following sequence:

Thus the common ratio of the sequence is .

...............................................................................................................................................

You drop a handball from a height of 1 meter. Each curved path has 64% of the height of the previous path.   A. A(n)= 100*(0.64)^n-1

kupik [55]3 years ago
4 0

Answer:

The correct choice is (A)

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If (5x− 4)(3x+ 7) = 15x²-ax-b,then find the value of a and b
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Answer:

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Step-by-step explanation:

Let's start by using distributive multiplication:

(a\pm b)(c\pm d)=ac\pm ad \pm bc \pm bd

So:

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Grouping like terms:

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Now, 15x^2+23x-28 is equal to:

15x^2-ax-b

In this sense:

15x^2+23x-28=15x^2-ax-b

In order to satisfied the equality:

23x=-ax\hspace{10}(1)\\\\and\\\\-28=-b\hspace{10}(2)

Hence, from (1), let's solve for a:

23x=-ax\\\\-a=\frac{23x}{x} \\\\-a=23\\\\a=-23

And from (2), let's solve for b:

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Let's verify the result evaluating the values of a and b into the original equation:

(5x-4)(3x+7)=15x^2+23x-28=15x^2 -ax -b\\\\(5x-4)(3x+7)=15x^2+23x-28=15x^2 -(-23)x -(28)\\\\(5x-4)(3x+7)=15x^2+23x-28=15x^2 +23x -28

As you can see, the values satisfy the equation, therefore, we can conclude they are correct.

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Answer:

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