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Rashid [163]
3 years ago
6

select three side lengths in centimeters that can form a right triangle 5cm 6cm 8cm 10cm 12cm

Mathematics
1 answer:
Nookie1986 [14]3 years ago
6 0

Answer:

10cm

Step-by-step explanation:

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H=10 cm <br>r= 7cm <br>calculate the volume of the cylinder ​
Stels [109]

Answer:

V = 1538.6 cm^3

Step-by-step explanation:

The volume of a cylinder is given by

V = pi r^2h  where r is the radius and h is the height

V = pi (7)^2 10

V = 3.14 (49)10

V = 1538.6 cm^3

7 0
3 years ago
Read 2 more answers
One diagonal of a rhombus has endpoints (-6, 9) and (-2, 1).
julsineya [31]

(2, 8) and (-10, 2)

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5 0
2 years ago
The school store sells pencils and erasers.
garri49 [273]

Answer:

$0.18

Step-by-step explanation:

we need to set up two simultaneous equations

using variables, pencils = p and erasers = e

3 pencils and 2 erasers, the cost is $0.76

3p + 2e = $0.76

2 pencils and 4 erasers, the cost is $1.04.

2p + 4e = $1.04

we now have

3p + 2e = $0.76

2p + 4e = $1.04

to make the number of erasers the same, multiply the first equation by 2 to give 4e

2(3p + 2e = $0.76)

6p + 4e = $1.52

now we have the same number of erasers for both equations

6p + 4e = $1.52

2p + 4e = $1.04

subtract across: 6p - 2p = 4p, 4e - 4e = 0, $1.52 - $1.04 = $0.48

we are left with 4p = $0.48

divide both sides by 4

p = $0.12

1 pencil = $0.12

go back to the start of both equations and use one of them to find 1 eraser. I'll use 3p + 2e = $0.76

input $0.12 in p

3($0.12) + 2e = $0.76

$0.36 + 2e = $0.76

subtract $0.36 on both sides

2e = $0.76 - $0.36

2e = $0.40

divide 2 on both sides

e = $0.20

1 eraser = $0.20

How much more does 1 eraser cost than 1 pencil?

we now know 1 pencil = $0.12 and 1 eraser = $0.20

find the difference between them

$0.20 - $0.12 = $0.18

final answer= $0.18

6 0
3 years ago
Help me please im begging​
WARRIOR [948]
What do you need help with?
8 0
3 years ago
Suppose that Matthew can choose to get home from work by car or bus.
Verizon [17]

Answer:

B-91%

Step-by-step explanation:

Bayes Theorem:

Two events, A and B.

P(B|A) = \frac{P(B)*P(A|B)}{P(A)}

In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.

In this question:

Event A: arriving home after 7 p.m.

Event B: getting home by bus.

When he chooses to get home by bus, he arrives home after 7 p.m. 25 percent of the time.

This means that P(A|B) = 0.25

Because the bus is cheaper, he uses the bus 70 percent of the time.

This means that P(B) = 0.7

Probability of getting home after 7 p.m.

70% of the time he uses bus, and by bus, he arrives arrives home after 7 p.m. 25 percent of the time.

100 - 70 = 30% of the time he uses the car, and by car, he arrives home after 7 p.m. 6 percent of the time.

So

P(A) = 0.7*0.25 + 0.3*0.06 = 0.193

What is the approximate probability that Matthew chose to get home from work by bus, given that he arrived home after 7 p.m.?

P(B|A) = \frac{0.7*0.25}{0.193} = 0.9067

Rouding up, 91%.

So the correct answer is:

B-91%

7 0
4 years ago
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