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jenyasd209 [6]
3 years ago
6

6. Peter is standing next to a flagpole and wants to

Mathematics
1 answer:
NikAS [45]3 years ago
3 0

Answer:

forstone

Step-by-step explanation:

sike I lied I dont know this RESPECTFULYY!!

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Sylvia enlarged a photo to make a 24 x 32 inch poster using the dilation DQ,4. What are the dimensions, in inches, of the origin
RSB [31]

Answer:

6 × 8

Step-by-step explanation:

Since the dilation factor is 4, and the image was ENLARGED, that means the original photo was smaller.  Smaller by a factor of 4.

So, we take the new dimensions (24x32) and we divide each side by the dilation factor of 4:

(24/4) x (32/4) = 6 x 8

It couldn't be the first answer choice (3x8) because  that doesn't maintain the ratio of the enlarge picture.  The other possible answers do match the right ratio... but only 6x8 is scaled by a factor of 4.

3 0
3 years ago
The sum of three numbers is 121 The third number is 3 times the second. The first number is 6 times the second. The first number
Mama L [17]

Answer:

The first number is

72.6

Step-by-step explanation:

Let second number be x.

First number= 6x

Third number= 3x

According to question,

6x+x+3x=121

or, 10x=121

or,x=121/10=12.1

First number= 6x=6×12.1=72.6

Third number=3x=3×12.1=36.3

3 0
2 years ago
Read 2 more answers
40, 10, 5/2 5/8... (fractions) is it arithmetic or geometric and what are the next two terms PLZ HELP DUE IN 10 MINS
patriot [66]

Answer:

Please check the explanation.

Step-by-step explanation:

Given the sequence

40,\:10,\:\frac{5}{2},\:\frac{5}{8}

A geometric sequence has a constant ratio 'r' and is defined by

\:a_n=a_0\cdot r^{n-1}

Computing the ratios of all the adjacent terms

\frac{10}{40}=\frac{1}{4},\:\quad \frac{\frac{5}{2}}{10}=\frac{1}{4},\:\quad \frac{\frac{5}{8}}{\frac{5}{2}}=\frac{1}{4}

The ratio of all the adjacent terms is the same and equal to

r=\frac{1}{4}

Thus, the given sequence is a geometric sequence.

As the first element of the sequence is

a_1=40

Therefore, the nth term is calculated as

\:a_n=a_0\cdot r^{n-1}

a_n=40\left(\frac{1}{4}\right)^{n-1}

Put n = 5 to find the next term

a_5=40\left(\frac{1}{4}\right)^{5-1}

a_5=40\cdot \frac{1}{4^4}

a_5=\frac{40}{4^4}

   =\frac{2^3\cdot \:5}{2^8}

a_5=\frac{5}{2^5}

a_5=\frac{5}{32}

now, Put n = 6 to find the 6th term

a_6=40\left(\frac{1}{4}\right)^{6-1}

a_6=40\cdot \frac{1}{4^5}

a_6=\frac{40}{4^5}

    =\frac{2^3\cdot \:5}{2^{10}}

a_6=\frac{5}{2^7}

a_6=\frac{5}{128}

Thus, the next two terms of the sequence 40, 10, 5/2, 5/8... is:

  • a_5=\frac{5}{32}
  • a_6=\frac{5}{128}
7 0
3 years ago
Suppose Maya made another sign with an area of 48 square inches. Would this sign be larger or smaller than the sign with an area
luda_lava [24]
Larger because I want the points and you are going to get an F
6 0
3 years ago
Solving quadratics equations by taking square root
Novay_Z [31]
#6
x^2 = 1
x = - 1 and x = + 1

#7
a^2 + 1 = 19
a^2 =18
a^2 =√ 9 <span>√ 2
a = + 3</span>√ 2 and a = - 3<span>√ 2</span>
4 0
3 years ago
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