Answer:

Explanation:
Molarity is found by dividing the moles of solute by liters of solution.

We are given grams of a compound and milliliters of solution, so we must make 2 conversions.
1. Gram to Moles
We must use the molar mass. First, use the Periodic Table to find the molar masses of the individual elements.
- C: 12.011 g/mol
- H: 1.008 g/mol
- O: 15.999 g/mol
Next, look at the formula and note the subscripts. This tells us the number of atoms in 1 molecule. We multiply the molar mass of each element by its subscript.
6(12.011)+12(1.008)+6(15.999)=180.156 g/mol
Use this number as a ratio.

Multiply by the given number of grams.

Flip the fraction and divide.


2. Milliliters to Liters
There are 1000 milliliters in 1 liter.

Multiply by 2500 mL.


3. Calculate Molarity
Finally, divide the moles by the liters.


The original measurement has 2 significant figures, so our answer must have the same. That is the hundredth place and the 3 tells us to leave the 7.

1 mole per liter is also equal to 1 M.

If there is an increase in industrial activity, that means that more heat will be dissipated to the atmosphere in the form of carbon dioxide. Industrialization requires fuel to keep the processes on the go. At the end of the pipeline, the combustion of fuel would result to carbon dioxide released to the atmosphere. That's how it is contributing to the global climate change through the greenhouse effect.
Answer:
Deforestation, increase wildlife extinction, ecosystem imbalances, soil erosion, migration and loss of species.
Explanation:
Global warming is warming the earth's surface temperature, which causes the changes in our ecosystem like deforestation, soil erosion, climate changes, migration and loss of species etc.
Global warming is caused by the 'Greenhouse effect', major gases are carbon dioxide(9-26%), methane(4-9%), water vapour(36-70%) ozone(3-7%) and nitrous oxide.
Global warming affects on the ocean include rising sea level, meiting glaciers, thermal expansion and ice sheets. It also cause the bird migration which carries high cost of predation and mortality.
Answer:
The major limitations of Newlands' law of octaves were : (i) It was applicable to only lighter elements having atomic masses upto 40 u, i.e., upto calcium. After calcium, the first and the eighth element did not have similar properties
Answer:
D. 0.75 grams
Explanation:
The data given on the iridium 182 are;
The half life of the iridium 182,
= 15 years
The mass of the sample of iridium, N₀ = 3 grams
The amount left, N(t) after two half lives is given as follows;

For two half lives, t = 2 × 
∴ t = 2 × 15 = 30


∴ The amount left, N(t) = 0.75 grams