Explanation;
Writing scientific notation :
- Move the decimal to the left side until single digit of number remains before the decimal.
- Then we will count the number of times we moved the decimal. Write this number as the exponential power of number '10'.
- For Example:
Radius of the sun = 696,000.0 kilometer
Radius of the sun can also be written as = 
Size of bacterial cell = 
millimeter
Size of bacterial cell can also be written as = 
Answer:
c. a process by which plants produce sugar using energy of sunlight
Answer:
Change in internal energy (ΔU) = -9 KJ
Explanation:
Given:
q = –8 kJ [Heat removed]
w = –1 kJ [Work done]
Find:
Change in internal energy (ΔU)
Computation:
Change in internal energy (ΔU) = q + w
Change in internal energy (ΔU) = -8 KJ + (-1 KJ)
Change in internal energy (ΔU) = -8 KJ - 1 KJ
Change in internal energy (ΔU) = -9 KJ
Answer:
0.077 M
Explanation:
Data Given :
The concentration of half normal (NaCl) saline = 0.45g / 100 g
So,
Volume of Solution = 100 g = 100 mL
Volume of Solution in Liter = 100 mL / 1000
Volume of Solution = 0.1 L
molar mass of NaCl = 58.44 g/mol
Molarity:
Molarity is the representation of the solution. It is amount of solute in moles per liter of solution and represented by M
Formula used for Molarity
M = moles of solute / Liter of solution . . . . . . . . . . (1)
Now to find number of moles of Nacl
no. of moles of NaCl = mass of NaCl / molar mass
no. of moles of NaCl = 0.45g / 58.44 g/mol
no. of moles of NaCl = 0.0077 g
Put values in the eq (1)
M = moles of solute / Liter of solution . . . . . . . . . . (1)
M = 0.0077 g / 0.1 L
M = 0.077 M
So the molarity of half-normal saline solution (0.45% NaCl) = 0.077 M
Answer: = 3.11 x 10^14 s^-1
Explanation:
Use the formula E = hv
This formula uses the assumption that the unit for energy is in Joules/photon.
124 kJ = 124000J
To get 124000J/mol into a unit of J/photons, we need to divide by the number of photons in a mole, which is 6.022 x 10^23.
And thus, we need
124000/6.022 x 10^23 = 2.06 x 10^-19J/photon
We can plug it in to E = hv by
2.06 x 10^-19J = (6.63 x 10^-34 J s)(v) Isolate v by
v = (2.06 x 10^-19J)/(6.63 x 10^-34 J s)
= 3.11 x 10^14 s^-1
