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rewona [7]
3 years ago
9

Which type of wave has the lowest energy of the following:

Chemistry
1 answer:
Tcecarenko [31]3 years ago
3 0

Answer:

use this to help u it starts from left to right

<u><em>Please mark as brainliest if answer is right</em></u>  

Have a great day, be safe and healthy  

Thank u  

XD

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The movement of charged particles cannot pass through an electrolyte to produce an electric current.
Rus_ich [418]

The movement of charged particles cannot pass through an electrolyte to produce an electric current.


True

False


FALSE

5 0
3 years ago
In cells, the role of the mitochondrion is to:
denis-greek [22]

Answer:

D produce energy

Explanation:

Mitochondria are membrane-bound cell organelles (mitochondrion, singular) that generate most of the chemical energy needed to power the cell's biochemical reactions.

7 0
2 years ago
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Find the number of moles of argon in 452 g of argon.
andrey2020 [161]

Answer: 13.31 moles.

Explanation: So take 452 grams of Argon and multiply by the molar mass of Argon. Your units will cancel out, leaving you with moles of Argon.

6 0
3 years ago
HELP ME PLEASE I NEED HELP SO BADLY
crimeas [40]

State the given:

Moles of Sulfur = 5 moles

Molar mass of Sulfur = 32.06g/mol

Look through the formulas:

Moles = Mass/Molar Mass

Rearrange the equation:

Mass = Moles x Molar mass

Plug in your given:

5 moles Sulfur   x   <u>32.06g</u>

                                 1 mol

<u>= 160.3g of Sulfur</u>

5 0
2 years ago
How many grams of Nacl would you need to prepare 200 ml of a 5 M SOLUTION. ?
vazorg [7]

Answer:

58.44 g of NaCl are needed.

Explanation:

Given data:

Mass of NaCl needed = ?

Volume of solution = 200 mL (200/1000 =0.2 L)

Molarity of solution = 5 M

Solution:

We will solve this problem through molarity formula.

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

Now we will put the values.

5 M = moles of solute / 0.2 L

Moles of solute = 5 mol/L × 0.2 L

Moles of solute = 1 mol

Mass of sodium chloride:

Mass = number of moles × molar mass

Mass = 1 mol × 58.44 g/mol

Mass = 58.44 g

Thus, 58.44 g of NaCl needed.

8 0
3 years ago
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