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3 years ago

A pool has a length of x - 5 and a width of x + 3. What is the area of the pool?

Mathematics

1 answer:

RoseWind [281]3 years ago

6 0

Answer:

Area or Volume?

Step-by-step explanation:

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A manufacturing company makes 1125 items every hour. which or these statements are true ? Check all that apply

Inessa05 [86]

Answer:

I need to see the statements to answer your question

4 0

3 years ago

Twice a first number decreased by a second number is 22. The first number increased by four times the second number is - 7.

AnnZ [28]

Answer:

Step-by-step explanation:

8 0

3 years ago

What is the common difference, d, in the arithmetic sequence defined by the formula below? an=2n+1

marishachu [46]

<h3>Answer:</h3>

d = 2

<h3>Solution:</h3>

We are given that the arithmetic progression is defined by :

➝ 2n + 1

Therefore, 

For first term

➙ n = 1

➝ 2 × 1 + 1

➝ 2 + 1

➝ 3

For second term

➙ n = 2

➝ 2 × 2 + 1

➝ 4 + 1

➝ 5

Common difference

➙ 2nd term - 1st term

➝ 5 - 3

➝ 2

<h3>More information:</h3>

The difference between the successive term and the preceding term is the difference of an arithmetic progression. It is always same for the same arithmetic progression.

5 0

2 years ago

How do you solve m+5n=p for m

WITCHER [35]

Answer:

my apologize for dont really understand the question! but this is what i got

m=p-5n or m=-5n+p

8 0

3 years ago

Read 2 more answers

Need help simplifying this

diamong [38]

The simplified answer is $\frac{\left(12 x^{2}+7 x y-4 y z-3 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}$ .

Step-by-step explanation:

$$\frac{3 y+2 x}{z+2 x}-\frac{2 y-3 x}{3 x+y}-\frac{2 z(y+3 x)}{6 x^{2}+3 x z+2 x y+y z}$

To add or subtract denominators of the fraction must be same.

If it is not the same, we must take LCM of the denominators. and so we can add the fractions.

To make the denominator same multiply the 1st term $(\frac{3x+y}{3x+y})$ and 2nd term by $(\frac{z+2x}{z+2x})$

= $\frac{(3 y+2 x)(3 x+y)}{(z+2 x)(3 x+y)}-\frac{(2 y-3 x)(z+2 x)}{(3 x+y)(z+2 x)}-\frac{2 z(y+3 x)}{6 x^{2}+3 x z+2 x y+y z}$

LCM of the denominators is 6x²+ 3xz + 2xy +yz.

Multiply the factors in the numerator.

= $\frac{\left(6 x^{2}+3 y^{2}+11 x y\right)}{(z+2 x)(3 x+y)}-\frac{\left(2 y z+4 x y-3 x z-6 x^{2}\right)}{(3 x+y)(z+2 x)}-\frac{2 z y+6 x z}{6 x^{2}+3 x z+2 x y+y z}$

Now, the denominators are same, you can subtract it.

= $\frac{\left(6 x^{2}+6 x^{2}+11 x y-4 x y-2 y z-2 y z+3 x z-6 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}$

= $\frac{\left(12 x^{2}+7 x y-4 y z-3 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}$

Thus the simplified solution is $\frac{\left(12 x^{2}+7 x y-4 y z-3 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}$

4 0

4 years ago