Answer:
Please find the solution in the attachment file.
Explanation:
Answer:−329.4 calorie
Explanation:Heat released by metal = q=m_mc_m(T_2-T1)q=m
m
c
m
(T
2
−T1)
m_m=50\ g\\c_m=0.108\ cal\ g^{-1}\ \degree C^{-1}\\q=50\times0.108(17-78)=-329.4\ caloriem
m
=50 g
c
m
=0.108 cal g
−1
°C
−1
q=50×0.108(17−78)=−329.4 calorie
Here minus sign indicate that heat is released
All the answers are on the actual periodic table. You should never be told to remember it so I think this is a recourse you are allowed to look at whilst doing your homework lol :) all the answers are written on it hope it helps
18.is D
19.is A
hope it's correct
<span>8.21 L of C3H8(g)
Lets take c as the molar volume at that temperature.
c L <><> 5c L
C3H8 (g) + 5O2 (g) --> 3CO2 + 4H2O + Q
8.21 L <><> x L
x = (8.21 * 5c)/c = 8.21 * 5 = 41.05 L O2 consumed for a 100% yield.</span>
