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Likurg_2 [28]
2 years ago
7

Please help me with this please help

Chemistry
1 answer:
djverab [1.8K]2 years ago
7 0

Answer:

I did this in class give me 10 min so i can find the anwsers

Explanation:

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You have 100 mL of a 12M solution of HCl, and you need to dilute it to 1.5M for an experiment. How many liters will your new sol
sashaice [31]

Answer:

800.0 mL.

Explanation:

  • To solve this problem; we must mention the rule states the no. of millimoles of a substance before and after dilution is the same.

<em>(MV)before dilution of HCl = (MV)after dilution of HCl</em>

M before dilution = 12.0 M, V before dilution = 100.0 mL.

M after dilution = 1.5 M, V after dilution = ??? mL.

∵ (MV)before dilution of HCl = (MV)after dilution of HCl

∴ (12.0 M)(100.0 mL) = (1.5 M)(V after dilution of HCl)

<em>∴ V after dilution of HCl = (12.0 M)(100.0 mL)/(1`.5 M) = 800.0 mL.</em>

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1. Three different observers measure the melting point of a substance and agree on the
Naddik [55]

d. precise but not accurte

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4 years ago
From the amount of NaOH added at the 1st equivalence point, calculate the original molarity of the acid. Carry out the same calc
gizmo_the_mogwai [7]

Answer:

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Explanation:

Using H2SO4 as acid, the reaction is as follow:

2NaOH  +  H2SO4 ⇒ Na2SO4  +  2H2O

Volume of acid = Va; Volume of base = Vb, Molar concentration of  acid = Ca; Molar concentration of base = Cb; Molarity of acid = A and Molarity of base = B

Ca*Va/Cb*Vb =A/B

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