The isotopes half life is 2 hours
Since given the following :
time = 8 hours × 3600s/hr = 28800 seconds
A₀ = 80 Bq as the first registration of detector counts per second
A = 5 Bq as the registration of detector counts per second eight hours later
Using the formula:
∴ A = A₀ e^-λt
∴ A/A₀ = e^-λt
∴ ln (A/A₀) = -λt
∴ λ = -ln (A/A₀) /t = ln2 / t_{1/2}
∴ t_{1/2} = -ln2 / ln(A/A₀) (t)
∴ t_{1/2} = -ln2 / ln(5/80) (8 hours) = 2 hours
Answer:
14 m/s²
Explanation:
Start with Newton's 2nd law: Fnet=ma, with F being force, m being mass, and a being acceleration. The applied forces on the left and right side of the block are equivalent, so they cancel out and are negligible. That way, you only have to worry about the y direction. Don't forget the force that gravity has the object. It appears to me that the object is falling, so there would be an additional force from going down from weight of the object. Weight is gravity (can be rounded to 10) x mass. Substitute 4N+weight in for Fnet and 1kg in for m.
(4N + 10 x 1kg)=(1kg)a
14/1=14, so the acceleration is 14 m/s²
This statement is missing the first sentence which states the horizontal acceleration.
I found that the desired horizontal acceleration is 15.0 m/s^2.
Now, you must use second law of Newton to calculate the force.
Second Law of Newton: F = m * a
=> F = 47 kg * 15 m/s^2 = 705 N
Answer: 705 N
Answer:
True
Explanation:
I just took the quiz and got it right.