Electromagnetic transverse waves
Answer:
The height of the image will be "1.16 mm".
Explanation:
The given values are:
Object distance, u = 25 cm
Focal distance, f = 1.8 cm
On applying the lens formula, we get
⇒ 
On putting estimate values, we get
⇒ 
⇒ 
⇒ 
As a result, the image would be established mostly on right side and would be true even though v is positive.
By magnification,
and
⇒ 
⇒ 
⇒ 
Answer:
Proton, stable subatomic particle that has a positive charge equal in magnitude to a unit of electron charge and a rest mass of 1.67262 × 10−27 kg, which is 1,836 times the mass of an electron.
Answer:0.1759 v
Explanation:
Intensity of wave at receiver end is
I=
I=
I=
Amplitude of electric field at receiver end

Amplitude of induced emf
=
=
=