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Solnce55 [7]
3 years ago
8

Which statement describes what most likely occurs when a compass is placed next to a simple circuit made from a battery, a light

bulb, and a wire?
A. A magnetic field created by the compass increases the current in the electrical circuit.
B. A magnetic field created by the compass causes the light bulb to stop working.
C. A magnetic field created by the electric current places negative charges on the compass.
D. A magnetic field created by the electric current causes the compass needle to move.

Physics
2 answers:
Nastasia [14]3 years ago
8 0
<span>When a compass is placed next to a simple circuit made from a
battery, a light bulb, and a wire, the magnetic field created by the
electric current in the wire causes the compass needle to move. (D)</span>
aleksley [76]3 years ago
6 0
D. A magnetic field created by the electric current causes the compass needle to move.
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Romashka [77]

-- The wavelength and the amplitude were described in my answer to your  previous question.

-- A "compression" is a place where the wave is <em>compressed</em>.  It's the darker section of the wave in the picture, where the wavelength is temporarily shorter, so several waves are all bunched up (compressed) in a small time.

-- A "rarefaction" is exactly the opposite of a "compression".  It's a place where the wave gets more "<em>rare</em>" ... the wavelength temporarily gets longer, so that several waves get stretched out, and there are fewer of them in some  period of time.  The arrow in the picture points to a rarefaction.

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What is the definition of bacteria ?
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Read 2 more answers
An electron is released from rest on the axis of a uniform positively charged ring, 0.200 m from the ring's center. If the linea
melisa1 [442]

Answer:

Velocity of the electron at the centre of the ring, v=1.37\times10^7\ \rm m/s

Explanation:

<u>Given:</u>

  • Linear charge density of the ring=0.1\ \rm \mu C/m
  • Radius of the ring R=0.2 m
  • Distance of point from the centre of the ring=x=0.2 m

Total charge of the ring

Q=0.1\times2\pi R\\Q=0.1\times2\pi 0.4\\Q=0.251\ \rm \mu C

Potential due the ring at a distance x from the centre of the rings is given by

V=\dfrac{kQ}{\sqrt{(R^2+x^2)}}\\

The potential difference when the electron moves from x=0.2 m to the centre of the ring is given by

\Delta V=\dfrac{kQ}{R}-\dfrac{kQ}{\sqrt{(R^2+x^2)}}\\\Delta V={9\times10^9\times0.251\times10^{-6}} \left( \dfrac{1}{0.4}-\dfrac{1}{\sqrt{(0.4^2+0.2^2)}} \right )\\\Delta V=5.12\times10^2\ \rm V

Let\Delta U be the change in potential Energy given by

\Delta U=e\times \Delta V\\\Delta U=1.67\times10^{-19}\times5.12\times10^{2}\\\Delta U=8.55\times10^{-17}\ \rm J

Change in Potential Energy of the electron will be equal to the change in kinetic Energy of the electron

\Delta U=\dfrac{mv^2}{2}\\8.55\times10^{-17}=\dfrac{9.1\times10^{-31}v^2}{2}\\v=1.37\times10^7\ \rm m/s

So the electron will be moving with v=1.37\times10^7\ \rm m/s

5 0
3 years ago
A body is at aheight of 81m and is ascending upwards with a velocity of 12m/s .a body of 2 kg weight is dropped from it.if g=10m
butalik [34]
First the velocity drops to zero in 1.2 secs. In those seconds it went upwards for 7.2 m, then it went from 87.2 to 0m. x-x0=v0*t+1/2*g*t^2 ergo t=sqrt(2x/g) that is 4.1761 s. Finally the total time required is 5.3761 s
7 0
3 years ago
Please help!!!
Zolol [24]

Answer:

48

Explanation:

you basically divide 1200 into 25

8 0
4 years ago
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