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WITCHER [35]
3 years ago
11

How would you change the distance between two charged particles to increase the electric force between them by a factor of 25?

Chemistry
1 answer:
valentinak56 [21]3 years ago
7 0

Answer:

reduce the distance by the factor of 5

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What is the molality of the resulting solution when 15.0 g of Licl is combined with 105 g of water? 0/1 point 0 1.42 m 2.95 m 3.
xenn [34]

Answer:

3.37 m

Explanation:

<u>Number of moles of solute present in 1 kg of solvent is termed as molality</u>

It is represented by 'm'.

Thus,

Molality\ (m)=\frac {Moles\ of\ the\ solute}{Mass\ of\ the\ solvent\ (kg)}

Given that:

The mass of LiCl = 15.0 g

Molar mass of LiCl = 42.394 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{15.0\ g}{42.394\ g/mol}

Moles= 0.3538\ mol

Mass of the solvent = 105 g

Also, 1 g = 0.001 g

So,

Mass of water (solvent) = 0.105 kg

Molality is:

Molality\ (m)=\frac {0.3538}{0.105}\ m

<u>Molality = 3.37 m</u>

3 0
3 years ago
6. How many moles of water would require 92.048 kJ of heat to raise its temperature from 34.0 °C to 100.0 °C? (3 marks)​
scoray [572]

Taking into account the definition of calorimetry, 0.0185 moles of water are required.

<h3>Calorimetry</h3>

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).

So, the equation that allows to calculate heat exchanges is:

Q = c× m× ΔT

where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

<h3>Mass of water required</h3>

In this case, you know:

  • Heat= 92.048 kJ
  • Mass of water = ?
  • Initial temperature of water= 34 ºC
  • Final temperature of water= 100 ºC
  • Specific heat of water = 4.186 \frac{J}{gC}

Replacing in the expression to calculate heat exchanges:

92.048 kJ = 4.186 \frac{J}{gC}× m× (100 °C -34 °C)

92.048 kJ = 4.186 \frac{J}{gC}× m× 66 °C

m= 92.048 kJ ÷ (4.186 \frac{J}{gC}× 66 °C)

<u><em>m= 0.333 grams</em></u>

<h3>Moles of water required</h3>

Being the molar mass of water 18 \frac{g}{mole}, that is, the amount of mass that a substance contains in one mole, the moles of water required can be calculated as:

amount of moles=0.333 gramsx\frac{1 mole}{18 grams}

<u><em>amount of moles= 0.0185 moles</em></u>

Finally, 0.0185 moles of water are required.

Learn more about calorimetry:

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8 0
3 years ago
In Bohr model N3 moves up to N 4 the electron occupies distinct energy states where energy is absorbed or emmitted
rewona [7]

Answer:

vkhcohvoccf

uxihfoydohfufyfocidicicugxigdixifxtxtduration jfhgxfcixig

cigcih

Explanation:

cihcohcohccohcjjcofidytstitddgggxogxxtdrrtteeeeeiiiixiiitttdooodooxyక్సజిఫ్స్ట్టిగ్గ్స్గ్డ్గ్

8 0
3 years ago
Student exploitation: electron configuration
adell [148]

E:2

M ummmmm

<em>try</em><em> </em><em>simplifying</em>

4 0
4 years ago
The number of molecules of ammonia, NH₃, in water solution required for complete ionization of one molecule of sulfuric acid, H₂
Natalija [7]

Answer:

6 that will be the answer

6 0
3 years ago
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