Iron (II) hydroxide, Fe(OH)2, is very insoluble in water. Hence, if it is produced during an aqueous reaction it will precipitat
e from solution. How many grams of sodium hydroxide (a strong base) must be added to 25.2 mL of a 0.605 M aqueous solution of iron (II) nitrate, in order to precipitate all of the iron as Fe(OH)2
1 answer:
Answer:1.2g of NaOH
Explanation:
First we put down the equation of reaction as shown in the image attached. From the equation of reaction, we can calculate the mass of sodium hydroxide that reacts with one mole of iron II ion according to the balanced stoichiometric equation. Using the information provided about the iron II nitrate, we can calculate the amount of Fe2+ that reacted with sodium hydroxide as shown in the image. Lastly, we use this information to obtain the mass of sodium hydroxide that reacted with the stipulated amount of NaOH.
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Explanation:
Chlorine has electronic configuration of 2 , 8 , 7
In n = 3 there are 7 electrons out of which 2 are in s , and 5 are in p . But out of 5 electrons in p , one electron jumps into d orbital . so the electronic configuration becomes as follows
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These orbitals like sp³d hybridise to form 7 degenerate orbitals out of which 2 orbitals contain electrons in pairs and rest three are singly occupied by electrons.( unpaired electrons )