Answer:
Molar mass of vitamin K = 450.56\frac{g}{mol}[/tex]
Explanation:
The freezing point of camphor = 178.4 ⁰C
the Kf of camphor = 37.7°C/m
where : m = molality
the relation between freezing point depression and molality is
Depression in freezing point = Kf X molality
Where
Kf = cryoscopic constant of camphor
molality = moles of solute dissolved per kg of solvent.
putting values
2.69°C = 37.7°C/m X molality
molality = 0.0714 mol /kg
moles of vitamin K = 0.0714X0.025 = 0.00178 mol
we know that moles are related to mass and molar mass of a substance as:
For vitamin K the mass is given = 0.802 grams
therefore molar mass =
Answer:
The fire may grow bigger, depending on the gas.
Explanation:
If you expose more air to a small flame then it could grow larger because air keeps fire alive.
This doesn’t seem like the full question
Complete question is;
A common way to describe the bonding energy curve for secondary bonding is the "6-12" potential. which states the bonding energy, E = - A/r^(6) + B/r^(12).
Write the expression that best represents the equilibrium bond length.
Answer:
Equilibrium bond length is;
r = (2B/A)^(1/6)
Explanation:
We are given bonding energy as;
E = - A/r^(6) + B/r^(12)
Now let's find the derivative of this bonding energy with respect to r and equate to zero to find the bonding length(r).
Thus;
dE/dr = 6A/r^(7) - 12B/r^(13)
Equating to zero gives;
6A/r^(7) - 12B/r^(13) = 0
6A/r^(7) = 12B/r^(13)
Divide both sides by 6 to give;
A/r^(7) = 2B/r^(13)
2B/A = (r^(13))/(r^(7))
2B/A = r^(13 - 7)
2B/A = r^(6)
Thus, r = (2B/A)^(1/6)