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3 years ago

Please help! due soon!

Chemistry

1 answer:

nekit [7.7K]3 years ago

7 0

Answer:

I think it's

there are the same number of molecules on each side of the equation, then a change of pressure makes no difference to the position of equilibrium

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In which state(s) of matter are the<br> particles free to move at Gut relative to<br> one another?

Colt1911 [192]

The answer is gas only.
hope this helps!

8 0

3 years ago

Phosphorus will ____ electrons to complete its octet changing into an ____

Paraphin [41]

Steal; Anion
This is the answer because phosphorous is very electronegative.

3 0

3 years ago

Match the following aqueous solutions with the appropriate letter from the column on the right.1. 0.19 m AgNO3 2. 0.17 m CrSO4 3

vichka [17]

Answer:

0.13 m of $Mn(NO_3)_2$ → Highest boiling point

0.19 m of $AgNO_3$ → Second Highest boiling point

0.17 m of $CrSO_4$ → Third highest boiling point

0.31 m Sucrose (nonelectrolyte) → Lowest boiling point

Explanation:

Elevation in boiling is given by :

$\Delta T_b=i\times k_b\times m$

Where :

i = van't Hoff factor

$k_b$ = Molal Elevation constant of solvent

m = molaity of the solution

1) 0.19 m of $AgNO_3$

$AgNO_3\rightarrow Ag^++NO_3^{-}$

i = 2 (electrolyte)

Molality of the solution = 0.19

Elevation is boiling point of solution:

$\Delta T_b=2\times k_b\times 0.19 m$

$\Delta T_b=0.38 m\times k_b$

2) 0.17 m of $CrSO_4$

$CrSO_4\rightarrow Cr^{2+}+SO_4^{2-}$

i = 2 (electrolyte)

Molality of the solution = 0.17

Elevation is boiling point solution :

$\Delta T_b=2\times k_b\times 0.17 m$

$\Delta T_b=0.34 m\times k_b$

3) 0.13 m of $Mn(NO_3)_2$

$Mn(NO_3)_2\rightarrow Mn^{2+}+2NO_3^{-}$

i = 3 (electrolyte)

Molality of the solution = 0.13

Elevation is boiling point solution :

$\Delta T_b=3\times k_b\times 0.13 m$

$\Delta T_b=0.39 m\times k_b$

4) 0.31 m Sucrose (nonelectrolyte)

i = 1 ( non electrolyte)

Molality of the solution = 0.31 m

Elevation is boiling point solution :

$\Delta T_b=1\times k_b\times 0.31 m$

$\Delta T_b=0.31 m\times k_b$

Higher the value of elevation in temperature higher will be the boiling point of the solution .

The decreasing order of solution from highest boiling point to lowest boiling point is :

$0.39 m\times k_b>0.38 m\times k_b>0.34 m\times k_b>0.31 m\times k_b$

0.13 m of $Mn(NO_3)_2$ → Highest boiling point

0.19 m of $AgNO_3$ → Second Highest boiling point

0.17 m of $CrSO_4$ → Third highest boiling point

0.31 m Sucrose (nonelectrolyte) → Lowest boiling point

6 0

3 years ago

Difference between proton and electron

Vanyuwa [196]

Answer:

An electron is a negatively charged component of an atom

the proton is a positively charged body.

Explanation:

3 0

2 years ago

The following list contains some common radicals. Using the charges on these ions and the idea of valence, predict the formulas

lesantik [10]

Answer : The formula for the compound sodium carbonate is $Na_2CO_3$

The formula for the compound potassium permanganate is $KMnO_4$

Explanation :

For formation of a neutral ionic compound, the charges on cation and anion must be balanced.

The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non-metals.

(a) Sodium carbonate

In the compound, the sodium metal forms an ionic compound with polyatomic anion (carbonate) $CO_3^{2-}$ .

Here, sodium is having an oxidation state of +1 called as $Na^{1+}$ cation and carbonate $CO_3^{2-}$ is an anion with oxidation state of -2. The charges are not balanced. So, the charges are balanced by the cris-cross method. Thus, the compound formed will be, $Na_2CO_3$

Hence, the formula for the compound sodium carbonate is $Na_2CO_3$

(b) Potassium permanganate

In the compound, the potassium metal forms an ionic compound with polyatomic anion (permanganate) $MnO_4^{1-}$ .

Here, potassium is having an oxidation state of +1 called as $K^{1+}$ cation and permanganate $MnO_4^{1-}$ is an anion with oxidation state of -1. The charges are balanced. Thus, the compound formed will be, $KMnO_4$

Hence, the formula for the compound potassium permanganate is $KMnO_4$

3 0

3 years ago