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Brilliant_brown [7]
3 years ago
5

Convert 345 NH3 grams to moles

Chemistry
2 answers:
7nadin3 [17]3 years ago
3 0
345 NH3 in moles is: 20.2577490294015 moles.
Dmitrij [34]3 years ago
3 0
M(NH₃)=345 g

M(NH₃)=A(N)+3A(H)
M(NH₃)=14.0+3·1.0=17.0g/mol

n(NH₃)=m(NH₃)/M(NH₃)

n(NH₃)=345g/17.0g/mol=20.3 mol
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A powder contains FeSO4 · 7 H2O (molar mass = 278.01 g/mol), among other components. A 3.055 g sample of the powder was dissolve
solong [7]

Answer:

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Explanation:

Step 1: Data given

Molar mass of FeSO4 * 7H2O = 278.01 g/mol

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Mass of the sample = 3.055 grams

Step 2: The balanced equation

4 Fe + 3O2 → 2Fe2O3

Step 3: Calculate moles Fe2O3

Moles Fe2O3 = mass Fe2O3 / molar mass Fe2O3

Moles Fe2O3 = 0.294 grams / 159.59 g/mol

Moles Fe2O3 = 0.00184 moles

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Step 4: The balanced equation

Fe + H2SO4 + 7H2O → FeSO4*7H20 + H2

Step 5: Calculate moles FeSO4* 7H2O

For 1 mol Fe we have 1 mol FeSO4*7H2O

For 0.00368 moles Fe we have 0.00368 moles FeSO4*7H2O

Step 6: Calculate the mass of FeSO4*7H2O

Mass FeSO4*7H2O = moles * molar mass

Mass FeSO4*7H2O = 0.00368 moles * 278.01 g/mol

Mass FeSO4*7H2O = 1.023 grams

The mass of FeSO4*7H2O is 1.023 grams

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Answer:

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