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Brilliant_brown [7]
3 years ago
5

Convert 345 NH3 grams to moles

Chemistry
2 answers:
7nadin3 [17]3 years ago
3 0
345 NH3 in moles is: 20.2577490294015 moles.
Dmitrij [34]3 years ago
3 0
M(NH₃)=345 g

M(NH₃)=A(N)+3A(H)
M(NH₃)=14.0+3·1.0=17.0g/mol

n(NH₃)=m(NH₃)/M(NH₃)

n(NH₃)=345g/17.0g/mol=20.3 mol
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1.

Explanation:

Hello,

In this case, for the given reaction we first assign the oxidation state for each species:

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Sn^0+2H_2O+4H^++4H^+N^{5+}O^{-2}_3  \rightarrow Sn^{4+}O_2 +4H^++4N^{4+}O^{2-}_2+4H_2O

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