Ask question

Ask question

All categories

3 years ago

13

In a student experiment, the empirical formula of a copper halide was found by adding aluminum metal to an aqueous solution of t

he halide, displacing copper metal. The copper metal was filtered, washed with distilled water, dried, and weighed; three separate determinations were performed. The copper halide solution contained 42.62 g of copper chloride per liter. The student recorded the following experimental data.Trial Volume of copper chloride solution Mass of filter paper Mass of filter paper with copper (ml) (g) (g)A 49.6 0.908 1.694B 48.3 0.922 1.693C 42.2 0.919 1.588Write the empirical formula of copper chloride based on the experimental data.

1 answer:

Radda [10]3 years ago

3 0

<u>Answer:</u> The empirical formula for the given compound is $CuCl_3$

<u>Explanation:</u>

We are given:

Mass of copper chloride in 1 L or 1000 mL of solution = 42.62 grams

<u>Taking Trial A:</u>

Volume of solution = 49.6 mL

Applying unitary method:

In 1000 mL of solution, the mass of copper chloride present is 42.62 grams

So, in 49.6 mL of solution, the mass of copper chloride will be = $\frac{42.62}{1000}\times 49.6=2.114g$

We are given:

Mass of filter paper = 0.908 g

Mass of filter paper + copper = 1.694 g

Mass of copper = [1.694 - 0.908] g = 0.786 g

Mass of chlorine in the sample = [2.114 - 0.786]g = 1.328 g

To formulate the empirical formula, we need to follow some steps:

<u>Step 1:</u> Converting the given masses into moles.

Moles of Copper = $\frac{\text{Given mass of Copper}}{\text{Molar mass of Copper}}=\frac{0.786g}{63.5g/mole}=0.0124moles$

Moles of Chlorine = $\frac{\text{Given mass of Chlorine}}{\text{Molar mass of Chlorine}}=\frac{1.328g}{35.5g/mole}=0.0374moles$

<u>Step 2:</u> Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.0124 moles.

For Copper = $\frac{0.0124}{0.0124}=1$

For Chlorine = $\frac{0.0374}{0.0124}=3.02\approx 3$

<u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of Cu : Cl = 1 : 3

Hence, the empirical formula for the given compound is $CuCl_3$

You might be interested in

A chemist divides a large sample of a mixture into three smaller portions. Each of these portions contains different ratios of t

ehidna [41]

Answer:

Heterogeneous mixture

Explanation:

A mixture is a substance that is made up of different components that are not chemically combined. For example, the air is a mixture containing gaseous components.
A pure substance, on the other hand, is a substance that contains similar particles. For example, an element is a pure substance with similar atoms and a compound is a pure substance with similar molecules.
A mixture may either be homogeneous or heterogeneous.
A homogeneous mixture contains various fractions of components in a single-phase while a heterogeneous mixture contains components in different phases and different ratios.

3 0

4 years ago

Read 2 more answers

In the Energy and Specific Heat lab, you measure the temperature change of water to study the specific heat of a metal. What sta

pshichka [43]

The question is incomplete, the complete question is;

In the Energy and Specific Heat lab, you measure the temperature change of water to study the specific heat of a metal. What statement explains the relationship between the water and the metal you are studying? Select one: O The heat lost by the metal plus the heat gained by the water equals 100. O The temperature change of the metal is equal to the temperature change of the water. O The heat lost by the metal is equal to the heat gained by the water. The initial temperature of the metal equals the initial temperature of the water

Answer:

The heat lost by the metal is equal to the heat gained by the water.

Explanation:

When the piece of metal is put into water, heat is lost by the metal and gained by the water.

Recall that energy is conserved hence heat lost by metal must be equal to heat gained by water.

Thus, the relationship between the metal under study and the water is that the metal looses heat to the water and heat lost by metal is equal to heat gained by water.

3 0

3 years ago

Name the following compound:<br><br> CH3 – CH2 – CH2 – O – CH2 – CH2 – CH2 – CH3

FrozenT [24]

THE COMPOUND IS: ethnoxybutane

4 0

3 years ago

Which is the more preferred fuel: one with a higher energy density or one with a lower energy density

Nana76 [90]

The higher the energy density of a fuel, the greater the amount of energy it has stored.

<h3>What is the energy density?</h3>

The energy density of a fuel is defined as the amount of energy it possesses per unit volume or per unit weight.

<h3>Characteristics of the energy density</h3>

It is the amount of energy accumulated in an energy vector per unit volume or mass.

In general, higher density energy sources and carriers are preferable, as many end uses require concentration of such energy.

The packaging of energy in liquid hydrocarbons is the one with the highest energy density, that is, the highest energy per volume unit, hence its high use in the transportation sector.

Therefore, we can conclude that in general, fuels, especially low molecular weight fuels, have high energy densities.

Learn more about the energy density here: brainly.com/question/2165966

5 0

3 years ago

Indicate the types of forces that are involved between the solute and solvent when forming a homogeneous solution between ch3ch2

Bess [88]

Answer:
Dispersion Forces are found between n-Pentane (CH₃-CH₂-CH₂-CH₂-CH₃) and n-Hexane (CH₃-CH₂-CH₂-CH₂-CH₂-CH₃).

Explanation:
Dispersion Forces are present and developed by those compounds which are non-polar in nature. In given statement n-Pentane and n-Hexane both are non-polar in nature as the electronegativity difference between Hydrogen atoms and Carbon atoms is less than 0.4.
When non-polar molecules approaches each other, a Dipole is induced in one of them, this step is known as Instantaneous Dipole, This generated Dipole on approaching another non-polar molecule induces dipole in it and the process propagates. Hence, creating intermolecular interactions.

8 0

3 years ago

Read 2 more answers