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Radda [10]
3 years ago
8

Three arithmetic means between 3 and -13

Mathematics
1 answer:
Mkey [24]3 years ago
5 0
What exactly are you trying to figure out
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Find x: a - bx = cx + d
V125BC [204]

Answer:

x= -(d-a)/(b+c)

Step-by-step explanation:

Move all terms to the left side and set equal to zero. Then set each factor equal to zero

5 0
3 years ago
1/3 of a cup of flour is used to make 6 cinnamon rolls. How much fliur is needed to make 1 cinnamon roll?
Debora [2.8K]
I hope this helps you

4 0
3 years ago
How do I find the value of x
IgorC [24]

Answer:

<u><em>The value of x is 2.6</em></u>

Step-by-step explanation:

<em>Use pythagorean theorem</em>

a^2+b^2=c^2

<em>Then substitute</em>

1^2+2.4^2=c^2

<em>Then evaluate</em>

1+5.76=c^2

<em>Add</em>

c^2=6.76

<em>Isolate c by finding the sqrt of 6.76</em>

c=2.6

3 0
3 years ago
Read 2 more answers
Help! <br> Which expression is equivalent? <br> On edge
Ira Lisetskai [31]

Answer: Choice B

x^{1/8}y^{8}

======================================================

Explanation:

The two rules we use are

(a*b)^c = a^c*b^c

(a^b)^c = a^{b*c}

When applying the first rule to the expression your teacher gave you, we can say that:

\left(x^{1/4}y^{16}\right)^{1/2} = \left(x^{1/4}\right)^{1/2}*\left(y^{16}\right)^{1/2}

Then applying the second rule lets us say

\left(x^{1/4}\right)^{1/2}*\left(y^{16}\right)^{1/2} = x^{1/4*1/2}*y^{16*1/2} = x^{1/8}y^{8}

Therefore,

\left(x^{1/4}y^{16}\right)^{1/2}  = x^{1/8}y^{8}

-------------

In short, we just multiplied each exponent inside by the outer exponent 1/2.

So that explains why the exponents go from {1/4,16} to {1/8,8} for x and y in that exact order.

7 0
3 years ago
If line r and line s are parallel and ∠2 measures 45°, what is the measure of ∠3?
Illusion [34]
The measure of anngle 3 is 135
3 0
3 years ago
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