Answer:
5.35m H2O2 x 34.02g/1m H2O2 = 182g H2O2
Explanation:
Answer: 0.27621 g
Explanation:
0.297 ml *0.930 g/ml=0.27621 g
The freezing point of a 1.324 m solution, prepared by dissolving biphenyl into naphthalene, is 71.12 ° C.
A solution is prepared by dissolving biphenyl into naphthalene. We can calculate the freezing point depression (ΔT) for naphthalene using the following expression.
where,
- i: van 't Hoff factor (1 for non-electrolytes)
- Kf: cryoscopic constant
- m: molality
The normal freezing point of naphthalene is 80.26 °C. The freezing point of the solution is:
The freezing point of a 1.324 m solution, prepared by dissolving biphenyl into naphthalene, is 71.12 ° C.
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Answer: The final temperature of the water will be
Explanation:
The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.
Q = Heat absorbed= Joules
m= mass of water =
c = specific heat capacity =
Initial temperature of the water = =
Final temperature of the water = = ?
Putting in the values, we get:
The final temperature of the water will be