1) At tne same temperature and with the same volume, initially the chamber 1 has the dobule of moles of gas than the chamber 2, so the pressure in the chamber 1 ( call it p1) is the double of the pressure of chamber 2 (p2)
=> p1 = 2 p2
Which is easy to demonstrate using ideal gas equation:
p1 = nRT/V = 2.0 mol * RT / 1 liter
p2 = nRT/V = 1.0 mol * RT / 1 liter
=> p1 / p2 = 2.0 / 1.0 = 2 => p1 = 2 * p2
2) Assuming that when the valve is opened there is not change in temperature, there will be 1.00 + 2.00 moles of gas in a volumen of 2 liters.
So, the pressure in both chambers (which form one same vessel) is:
p = nRT/V = 3.0 mol * RT / 2liter
which compared to the initial pressure in chamber 1, p1, is:
p / p1 = (3/2) / 2 = 3/4 => p = (3/4)p1
So, the answer is that the pressure in the chamber 1 decreases to 3/4 its original pressure.
You can also see how the pressure in chamber 2 changes:
p / p2 = (3/2) / 1 = 3/2, which means that the pressure in the chamber 2 decreases to 3/2 of its original pressure.
Answer: gradual increase in temperature of ice from −15°C to 0°C, holding at 0°C as ice melts to water
Explanation: The heat used to convert solid to liquid is gained by molecules to gain kinetic energy and thus the molecules start moving faster and the temperature increases.
But as the melting point is approached i.e. , the temperature remains constant as now the heat given is used to break the inter molecular forces and thus is not reflected in terms of temperature increase. This hidden heat is called as latent heat.
The temperature remains constant till the phase change is complete.
Answer:
tupgstdtliylyf disparities in the first to comment on this device is not a little bit of a very happy with the first to comment hi friends how true and 7सुप्रभात मैं थोड़ा सा हूँ
Answer: 5 water molecules
Explanation:
Decomposition of hydrated copper sulphate is given by:
Molar mass of = 159.6 g/mol
According to stoichiometry:
(159.6+18x) g of decomposes to give = 159.6g of
Thus 7.74 g of decomposes to give= g
But it is given 7.74 g of a sample of hydrated salt was found to contain 4.95 g of anhydrous salt.
Thus we can equate the two equations:
x=5
Thus there are 5 water molecules associated with each formula unit.
The answer is C ionic bonds