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3 years ago

Ol helvrcrffffcrcrrcffcddcdcr3d

Mathematics

1 answer:

balandron [24]3 years ago

7 0

Answer:

Step-by-step explanation:

Figure A is 5 spaces down reflected off of figure B.

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A tank currently holds 5 gallons of water. It is being filled at the rate of 1/4 gallon per minute. How long will it take for th

Verdich [7]

So we know the tank already has 5 gallons and we need 9. This means we need 4 more gallons in order to fill up the tank.

If 1/4 gallon is being filled per minute we need to find out how many 1/4 gallons makes up 4 gallons in total.

4 of the 1/4 gallons makes up 1 whole gallon. So since we need 4 whole gallons we would need 16 of the 1/4 gallons.

This means that it will take 16 minutes for the tank to hold 9 gallons of water.

6 0

3 years ago

Read 2 more answers

Please help me and make sure to show your work

irina1246 [14]

Answer: C 20

Explanation: Plug in 2 for k.

2^2 - (2-10) + 4(2) = 20

4 0

3 years ago

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Sid goes to the store and buys a shirt for $65. The store has sales tax rate of 5.4%. How much tax will Sid have to pay?

mojhsa [17]

Answer:

$3.51

Step-by-step explanation:

We change 5.4% into a decimal which is .054, we then multiply 65 by .054

$65 x .054 = $3.51

3 0

3 years ago

I NEED HELP PLZZ ASAP!!!

Crazy boy [7]

Answer:

612 I'm pretty sure.

Hope this helps!

Narancia out~!

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3 years ago

Two brands of AAA batteries are tested in order to compare their voltage. The data summary can be found below. Find the 93% conf

kobusy [5.1K]

Answer:

$(\bar X_1 -\bar X_2) \pm z_{\alpha/2} \sqrt{\frac{s^2_1}{n_1}+\frac{s^2_}{n_2}}$

And replacing we got:

$(9.2 -8.8) - 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.2903$

$(9.2 -8.8) + 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.5097$

And the confidence interval for the difference of means would be given by:

$0.2903 \leq \mu_1 -\mu_2 \leq 0.5097$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

We have the following data given:

$\bar X_1 = 9.2 , \bar X_2 = 8.8, \sigma_1= 0.3, n_1 = 27, \sigma_2 = 0.1, n_2 = 30$

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 93% of confidence, our significance level would be given by $\alpha=1-0.93=0.07$ and $\alpha/2 =0.035$ . And the critical value would be given by:

$z_{\alpha/2}=-1.811, z_{1-\alpha/2}=1.811$

The confidence interval is given by:

$(\bar X_1 -\bar X_2) \pm z_{\alpha/2} \sqrt{\frac{s^2_1}{n_1}+\frac{s^2_}{n_2}}$

And replacing we got:

$(9.2 -8.8) - 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.2903$

$(9.2 -8.8) + 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.5097$

And the confidence interval for the difference of means would be given by:

$0.2903 \leq \mu_1 -\mu_2 \leq 0.5097$

4 0

3 years ago