After the collision, the momentum didn't change, so the total momentum in x and y are the same as the initial.
The x component was calculated by subtracting the initial momentum (total) minus the momentum of the first ball after the collision
In the y component, as at the beginning, the total momentum was 0 in this axis, the sum of both the first and struck ball has to be the same in opposite directions. In other words, both have the same magnitude but in opposite directions
This is for both balls after the collision, but one goes in a positive and the other in a negative direction.
<span>So
the mural has an area of 18m squared
=> A = 18m^2
in getting the area of a square we use to formula = s^2, but since the area is
already given, we need to find the value
of each sides of the square. Thus, we simply need to do it backward.
we need to find the square root of the area
=> square root of 18m^2
=> 4.24m
Therefore that mural has a sides of approximately 4.24 meters</span>
Answer:
the buoyant force acting on the ice cube is 0.119 N
Explanation:
given,
volume of ice cube = 15 cm³ = 15 × 10⁻⁶ m³
density of ice cube = 917 kg/m³
density of ethyl alcohol = 811 kg/m³
buoyant force = ?
The density of ice is more than ethyl alcohol hence it will sink.
buoyant force acting on the ice cube = ρ V g
= 811 × 15 × 10⁻⁶ × 9.81
=0.119 N
so, the buoyant force acting on the ice cube is 0.119 N
Hi!Schrodinger equation is written as HΨ = EΨ, where h is said to be a Hamiltonian operator.
Answer:
a)It is NOT possible using this telescope, to see the two stars as separate stars
b)
Explanation:
From the question we are told that:
Diameter of lens,
Distance from both star 
Distance between both stars 
Wavelength of light 
Generally the equation for angle subtended by the two stars at the lens is mathematically given by
Generally the equation for minimum angular separation of two object is mathematically given by
Therefore
It is NOT possible using this telescope, to see the two stars as separate stars
b)
Generally the equation for minimum diameter of the lens is mathematically given by
