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Anettt [7]
3 years ago
11

5 WILL PAY YOU CASH APP IF YOU ANSWER

Physics
2 answers:
Neko [114]3 years ago
6 0

Answer:

Dogs make good therapy pets because they usually crave lots of attention and affection.

Mazyrski [523]3 years ago
4 0

Answer: In 2010, about 24,000 therapy dogs were registered with Therapy Dogs International

Explanation:

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A butcher has a beam balance and masses 0.5kg and 2kg.How would he measure 1.5kg of meat on the balance at once
LekaFEV [45]

Answer and Explanation:

  • The butcher will balance the meat and the 0.5 kg mass on one side of the beam balance and 2 kg mass on the other side of the beam balance.
  • By so doing, when the beam balances then the amount of meat measured will be exactly 1.5 kg as required. Since the 1.5 kg meat and 0.5 kg mass is equivalent to the 2 kg on the other side of the beam balance.
6 0
3 years ago
In a laboratory, you determine that the density of a certain solid is 5.23× 10 −6 kg/m m 3 . convert this density into kilograms
tamaranim1 [39]

Density is given as

\rho = 5.23 * 10^{-6} kg/mm^3

now we have to convert this density into kg/m^3

now we have

1 m = 1000 mm

\rho = 5.23 * 10^{-6} \frac{kg}{(1*10^-3 m)^3}

\rho = 5.23 * 10^{-6} \frac{1*10^9 kg}{m^3}

\rho = 5.23 * 10^3 kg/m^3

\rho = 5230 kg/m^3

8 0
3 years ago
A light bulb emits light that travels uniformly in all directions. Detailed measurements show that at a distance of 56 m from th
vladimir1956 [14]

Complete question:

A light bulb emits light that travels uniformly in all directions. Detailed measurements show that at a distance of 56 m from the bulb, the amplitude of the electric field is 3.78 V/m. What is the average intensity of the light?

Answer:

The average intensity of the light is 0.02 W/m²

Explanation:

Given;

Amplitude of the electric field, E₀ = 3.78 V/m

The average intensity of the light is calculated as follows;

I_{avg} = \frac{c\epsilon_0 E_0^2}{2}

where;

I_{avg} is the average intensity of the light

c is speed of light = 3 x 10⁸ m/s

I_{avg} = \frac{(3\times 10^8)(8.85 \times 10^{-12}) (3.78)^2}{2} \\\\I_{avg} = 0.01897 \ W/m^2\\\\I_{avg} = 0.02 \ W/m^2

Therefore, the average intensity of the light is 0.02 W/m²

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8.05 that is the answer lllllllll
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