Density is given as

now we have to convert this density into 
now we have





 
        
             
        
        
        
Complete question:
A light bulb emits light that travels uniformly in all directions. Detailed measurements show that at a distance of 56 m from the bulb, the amplitude of the electric field is 3.78 V/m. What is the average intensity of the light?
Answer:
The average intensity of the light is 0.02 W/m²
Explanation:
Given;
Amplitude of the electric field, E₀ = 3.78 V/m
The average intensity of the light is calculated as follows;

where;
 is the average intensity of the light
 is the average intensity of the light
c is speed of light = 3 x 10⁸ m/s

Therefore, the average intensity of the light is 0.02 W/m²
 
        
             
        
        
        
The answer is c to take a pictures with the camera in the metal hall
        
             
        
        
        
8.05 that is the answer lllllllll