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alex41 [277]
3 years ago
9

A state patrol officer saw a car start from rest at a highway​ on-ramp. She radioed ahead to another officer 20 mi along the hig

hway. When the car reached the location of the second officer 19 min​ later, it was clocked going 60​ mi/hr. The driver of the car was given a ticket for exceeding the 60​ mi/hr speed limit. Why can the officer conclude that the driver exceeded the speed​ limit?
Physics
1 answer:
Vikentia [17]3 years ago
5 0

Answer:

We know from the basic speed distance relation that

Speed=\frac{Distance}{Time}

Since the car started from rest and it covered the distance between the 2 officer's in 19 minutes we have speed of the car

Speed=\frac{Distance}{Time}\\\\Speed=\frac{20}{\frac{19}{60}}=63.16mph

Which clearly exceeds the limit of 60\frac{mi}{hr}

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Ngan has a weight of 314.5 N on Mars and a weight 833.0 N on Earth. What is Ngan's mass on Earth?
mr_godi [17]

Ngan's mass on earth is 85kg.

Ngan has a weight on Mars = 14.5 N

Ngan’s weight on Earth = 833.0 N

Ngan’s mass on Earth = ?

<span>Fg,earth = mg(earth)</span>

<span>M = Fg,earth </span><span>/ g(earth)</span>

<span>M = 833.0 N / 9.8 m/s2</span>

<span>M = 85 kg</span>

4 0
3 years ago
Read 2 more answers
How much work is done if 10 N is applied to a 5kg object for 10 meters if there is an opposing force of 5 N
BlackZzzverrR [31]

Answer:

50 J

Explanation:

The net force acting on the box is given by the algebraic sum of the two forces, so:

F=10 N -5 N = 5 N

The net work done on the box is equal to (assuming the net force is parallel to the displacement of the object)

W=Fd

where

F = 5 N is the net force on the object

d = 10 m is the displacement of the object

Substituting,

W=(5 N)(10 m)=50 J

5 0
4 years ago
Car a with mass 1,783 kg collides with stationary 1600 kg car b. they become locked together after the collision and move with s
ValentinkaMS [17]

The initial speed of car A is 15.18 m/s.

Momentum is defined as mass in motion. If there are two objects (the two objects in motion or only one object in motion and the other in stationary) that collide and no other forces work in the system, the law of momentum conservation applies in the system.

p=p'

pa+pb = pa'+pb'

(ma×va) + (mb×vb) = (ma×va') + (mb×vb')

  • ma = mass of object A (kg) = 1,783 kg
  • mb = mass of object B (kg) = 1,600 kg
  • va = speed of object A before collides (m/s)
  • va' = speed of object A after collides (m/s) = 8 m/s
  • vb = speed of object B before collides (m/s) = 0 m/s
  • vb' = speed of object B after collides (m/s) = 8 m/s
  • p = momentum before collision (Ns)
  • p' = momentum after collision (Ns)

(ma×va) + (mb×vb) = (ma×va') + (mb×vb')

(1,783×va) + (1,600×0) = (1,783×8) + (1,600×8)

(1,783×va) + 0 = 14,264+12,800

(1,783×va) = 27,064

va \:=\: \frac{27,064}{1.783}

va = 15.18 m/s

Learn more about The law of momentum conservation here: brainly.com/question/7538238

#SPJ4

3 0
1 year ago
If v = 5.00 meters/second and makes an angle of 60° with the negative direction of the y–axis, calculate all possible values of
Goshia [24]
Vx = + 4.33 m/s. Hope this helps
8 0
3 years ago
What is the difference between collinear and coplanar
DIA [1.3K]

Answer:

Collinear is when points are in the same straight line but coplanar is when points are all on the same plane.

4 0
3 years ago
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