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dimaraw [331]
3 years ago
7

how fast is a ball going when it hits the ground after being dropped from a height of 16m the acceleration of gravity is 9.8

Physics
1 answer:
Aneli [31]3 years ago
8 0

Answer:

17.7 m/s

Explanation:

Given:

y₀ = 0 m

y = 16 m

v₀ = 0 m/s

a = 9.8 m/s²

Find: v

v² = v₀² + 2a (y − y₀)

v² = (0 m/s)² + 2 (9.8 m/s²) (16 m − 0 m)

v = 17.7 m/s

The ball is moving at a speed of 17.7 m/s when it hits the ground.

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Answer:

The answer to your question is letter A.     r = 1.07 x 10⁻¹⁴ m

Explanation:

Data

F = 2 N

d = ?

q = 1.6 x 10 ⁻¹⁹ C

k = 8.987 Nm²/C²

Formula

                 F = K\frac{q1q2}{r^{2}}

Solve for r

                r = \sqrt{\frac{kq1q2}{F}}

Substitution

                r = \sqrt{\frac{8.987 x 10^{9}x1.6 x 10^{-19} x 1.6 x 10x^{-19}}{2}}

Simplification

                r = \sqrt{\frac{2.3 x 10^{-28}}{2}}

                r = \sqrt{1.15 x 10^{-24}}

Result

                r = 1.07 x 10⁻¹⁴ m

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Consider a series RLC circuit where R = 855 Ω and C = 6.25 μF. However, the inductance L of the inductor is unknown. To find its
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Answer:

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