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Kipish [7]
3 years ago
8

Two or more different monomers will link to form a

Physics
1 answer:
-BARSIC- [3]3 years ago
7 0

d. natural gas is the answer

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Please help giving 15 points<br> How do you calculate the density of an object?
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You first find the mass and the volume of that object. Then you divide mass ÷ volume
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Why is specific heat important
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Hey!!

here is your answer >>>

Specific heat is the amount of heat required to raise the temperature of a unit substance!. The most common example!. The specific heat of water is 1 !. And, lot of plays and animals live under the water and if the specific heat of the water would be low, then the aquatic organisms would die, but the specific heat is high and it is hard for the sun to increase the temperature!.

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What is the slope of the line plotted below?<br> A. 1.33<br> B. -1.33<br> C. -0.6<br> D. 0.6
Naya [18.7K]

Answer:

C. -0.6

Explanation:

Line is passing through the points ( - 3, 1) & (2, - 2)

Slope of line

=  \frac{ - 2 - 1}{2 - ( - 3)}  =  \frac{ - 3}{2 + 3}  =  \frac{ - 3}{5}  =  - 0.6 \\

4 0
4 years ago
At a circus, a human cannonball is shot from a cannon at 15m/s at an angle of 40° above horizontal. She
Citrus2011 [14]

Answer:

a

The height is   H  = 6.74 \  m

b

The horizontal distance is  D  = 23.74 \  m

Explanation:

From the question we are told that

  The speed is  v  =  15 \  m/s

  The angle is  \theta  =  40^o

   The height of the cannon from the ground is  h  =  2 m

  The distance of the net from the ground is k  =  1 m

 

Generally the maximum height she reaches is mathematically represented as  

     H  =  \frac{v^2 sin^2 \theta }{2 *  g }  +  h

=>    H  =  \frac{(15)^2 [sin (40)]^2 }{2 * 9.8}  +  2

=>    H  = 6.74 \  m

Generally from kinematic equation  

    s = ut + \frac{1}{2} at^2

Here s is the displacement which is mathematically represented as

         s  =  [-(h-k)]  

    =>  s =  -(2-1)

    =>  s  = -1 m

There reason why s =  -1 m is because upward motion canceled the downward motion remaining only the distance of the net from the ground which was covered during the first half but not covered during the second half

     a =  -g = -9.8

    u  =  v sin (\theta)

So

    -1 = (vsin 40 )t + \frac{1}{2} * (-9.8) t^2

=>  -4.9t^2 + 9.6418t + 1 = 0

using  quadratic formula to solve the equation we have

    t  =  2.07 \  s

Generally distance covered along the horizontal is  

   D  =  v cos (40) *  2.07

=>   D  =  15 cos (40) *  2.07

=>   D  = 23.74 \  m

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3 years ago
HELP ASAP!!!! SCIENCE LOVERS !!! What do the lines making a circle around the LOW-PRESSURE area indicate?
Degger [83]
1 is D.
2 is A.

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