X = number of tickets sold in advance, and thus cheaper.
x + 206 = number of tickets sold at the door.
now, the ones sold at the door, are more expensive and is more than the early sold tickets, as you know is x + 206.
now, if the early ones cost each one 6 bucks, then the cost for all of them is 6*x, or 6x.
the ones sold at the door are 10 bucks each, and therefore their total cost is 10(x + 206).
now, we know sales in total for both was 6828, therefore,
![\bf \stackrel{in~advance}{6x}~~+\stackrel{at~the~door}{10(x+206)}=6828\implies 6x+10x+2060=6828 \\\\\\ 16x=4768\implies x=\cfrac{4768}{16}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7Bin~advance%7D%7B6x%7D~~%2B%5Cstackrel%7Bat~the~door%7D%7B10%28x%2B206%29%7D%3D6828%5Cimplies%206x%2B10x%2B2060%3D6828%0A%5C%5C%5C%5C%5C%5C%0A16x%3D4768%5Cimplies%20x%3D%5Ccfrac%7B4768%7D%7B16%7D)
and surely you'd know what that is.
how many were sold at the door? well, x + 206.
Answer:
![2x^3+8x^2-3x=0](https://tex.z-dn.net/?f=2x%5E3%2B8x%5E2-3x%3D0)
Step-by-step explanation:
![2x (2x^2+8x-6)=2\\multiply-all-in-bracets-by-2x\\4x^3+16x^2-6x=2\\devide-all-by-2\\2x^3+8x^2-3x=0](https://tex.z-dn.net/?f=2x%20%282x%5E2%2B8x-6%29%3D2%5C%5Cmultiply-all-in-bracets-by-2x%5C%5C4x%5E3%2B16x%5E2-6x%3D2%5C%5Cdevide-all-by-2%5C%5C2x%5E3%2B8x%5E2-3x%3D0)
Answer:
The answer is 16
Step-by-step explanation:
if you multiply 3 1/2 by 2 that would equal 7 and 2 1/4 by 4 it would equal 9.
can you tell me what the points are because the graph is somewhat blurry