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Alecsey [184]
3 years ago
5

What is a by-product of a nuclear power plant?

Chemistry
1 answer:
Mariana [72]3 years ago
6 0

Answer:

There are four categories of byproduct material: Radioactive material that results from the fissioning, or splitting apart, of enriched uranium or plutonium in nuclear reactors. Examples include cobalt-60, cesium-137 and iridium-192. Tailings or waste produced by processing uranium or thorium from ore.

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Air bags are activated when a severe impact causes a steel ball to compress a spring and electrically ignite a detonator cap. Th
Vlada [557]

Answer:

the mass required to inflate a 72 L bag is 191.491 g

Explanation:

reaction:

  • 2 NaN3 ↔ 2 Na + 3 N2

conditions:

  • V = 72.0 L
  • STP: P = 1 atm  ∧ T = 298 K

gas law:

  • PV = RTn
  • R = 0.082 atm * L / K * mol

⇒ n = PV / RT

⇒ n = ((1 atm) * ( 72.0 L)) / (0.082 atm*L / K*mol) * (298 K)

⇒ n = 2.946 mol

⇒ m = n * Mw = ( 2.946 mol ) * ( 64.99 g/mol)

⇒ m = 191.491 g

7 0
4 years ago
Who is good at chemistry?! HMU asap!!!​
____ [38]
Id say i’m good i guess. send links for the brainly problems u need help with!
6 0
3 years ago
What would be the correct answer please help!
bogdanovich [222]

Answer:

first number is the correct answer

6 0
3 years ago
Read 2 more answers
A balloon is filled with 3.0 l of helium at 20oc. at what temperature will the balloon be one-half that volume (1.5 l
timama [110]

<span>Answer<span>1. A certain mass of gas in a 2.00 L container has a pressure of 164 kPa. Calculate the new pressure of the gas if the volume of the container is reduced to 1.00L</span></span>
7 0
3 years ago
Be sure to answer all parts. What is the [H3O+] and the pH of a buffer that consists of 0.26 M HNO2 and 0.89 M KNO2? (K, of HNO2
Aleksandr-060686 [28]

Answer : The H_3O^+ ion concentration is, 1.12\times 10^{-3}M and the pH of a buffer is, 2.95

Explanation : Given,

K_a=7.1\times 10^{-4}

Concentration of HNO_2 (weak acid)= 0.26 M

Concentration of KNO_2 (conjugate base or salt)= 0.89 M

First we have to calculate the value of pK_a.

The expression used for the calculation of pK_a is,

pK_a=-\log (K_a)

Now put the value of K_a in this expression, we get:

pK_a=-\log (7.1\times 10^{-4})

pK_a=4-\log (7.1)

pK_a=3.15

Now we have to calculate the pH of the solution.

Using Henderson Hesselbach equation :

pH=pK_a+\log \frac{[Salt]}{[Acid]}

pH=pK_a+\log \frac{[KNO_2]}{[HNO_2]}

Now put all the given values in this expression, we get:

pH=3.15+\log (\frac{0.89}{0.26})

pH=2.95

The pH of a buffer is, 2.95

Now we have to calculate the H_3O^+ ion concentration.

pH=-\log [H_3O^+]

2.95=-\log [H_3O^+]

[H_3O^+]=1.12\times 10^{-3}M

The H_3O^+ ion concentration is, 1.12\times 10^{-3}M

4 0
3 years ago
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