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GarryVolchara [31]
3 years ago
5

3. Which of the following affects the angle at which the sun's rays hit Earth?

Chemistry
1 answer:
AnnZ [28]3 years ago
4 0

Answer:weather

Explanation:

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in disodium phosphate = 4 oxygen atoms

in phosphoric acid = 1 oxygen atom

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<span>The human body is organized at different levels, starting with the cell. Cells are organized into tissues, and tissues form organs. Organs are organized into organ systems such as the skeletal and muscular systems.</span>
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An Arrhenius base is a substance that increases the concentration of which ion in water solution?
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When 1.025 g of naphthalene (c10h8) burns in a bomb calorimeter, the temperature rises from 24.25°c to 32.33°c. find δerxn for t
Goryan [66]

Answer : The \Delta E for the combustion of naphthalene is 5161.25KJ/mole

Solution : Given,

Mass of naphthalene = 1.025 g

Initial temperature = 24.25^oC

Final temperature = 32.33^oC

Specific heat capacity of calorimeter = 5.11KJ/^oC

Molar mass of naphthalene = 128 g/mole

First, we have to calculate the heat absorbed, q

Formula used :

q=c\times \Delta T=c\times (T_{final}-T_{initial})

Now put all the given values in this formula, we get

q=(5.11KJ/^oC)\times (32.33^oCT-24.25^oC)=41.29KJ

Now we have to calculate the moles of naphthalene.

Moles of C_{10}H_{8} = \frac{\text{ Mass of }C_{10}H_{8}}{\text{ Molar mass of }C_{10}H_{8}}=\frac{1.025g}{128g/mole}=0.0080moles

Now we have to calculate the \Delta E for combustion of naphthalene.

\Delta E=\frac{q}{n}

where,

q = heat absorbed

n = number of moles

Now put all the values in this formula, we get

\Delta E=\frac{41.29KJ}{0.0080moles}=5161.25KJ/mole

Therefore, the \Delta E for the combustion of naphthalene is 5161.25KJ/mole

6 0
2 years ago
HELP IM BEING TIMED: btw its science im just putting some thing random
neonofarm [45]

Answer:

I thinks something bad will happen but science can change so im not sure

Explanation:

Science changes because of diffrent thing like enviorment

4 0
3 years ago
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