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GarryVolchara [31]

2 years ago

5

3. Which of the following affects the angle at which the sun's rays hit Earth?

1 answer:

AnnZ [28]2 years ago

4 0

Answer:weather

Explanation:

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Almost 99% of the Earth's atmosphere is made up of two gases. What ere the two gases and the percents of each?

Gwar [14]

Answer:

21% oxygen and 78%nitrogen

Explanation:

6 0

2 years ago

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In a pendulum, a continuous change occurs between kinetic energy and

Masja [62]

It should be potential energy!!!

7 0

3 years ago

Magnesium reacts with Oxygen gas forming Magnesium oxide as shown;

LuckyWell [14K]

Molar mass:

O2 = 16 x 2 = 32.0 g/mol Mg = 24 g/mol

<span>2 Mg(s) + O2(g) --->2 MgO(s)
</span>
2 x 24.0 g Mg -------------> 32 g O2
5.00 g Mg -----------------> ( mass of O2)

mass of O2 = 5.00 x 32 / 2 x 24.0

mass of O2 = 160 / 48

= 3.33 g of O2

hope this helps!

5 0

3 years ago

A tank contains 90 kg of salt and 2000 L of water. Pure water enters a tank at the rate 6 L/min. The solution is mixed and drain

sashaice [31]

Answer:

a) 90 kg

b) 68.4 kg

c) 0 kg/L

Explanation:

Mass balance:

$-w=\frac{dm}{dt}$

w is the mass flow

m is the mass of salt

$-v*C=\frac{dm}{dt}$

v is the volume flow

C is the concentration

$C=\frac{m}{V+(6-3)*L/min*t}$

$-v*\frac{m}{V+(6-3)*L/min*t}=\frac{dm}{dt}$

$-3*L/min*\frac{m}{2000L+(3)*L/min*t}=\frac{dm}{dt}$

$-3*L/min*\frac{dt}{2000L+(3)*L/min*t}=\frac{dm}{m}$

$-3*L/min*\int_{0}^{t}\frac{dt}{2000L+(3)*L/min*t}=\int_{90kg}^{m}\frac{dm}{m}$

$-[ln(2000L+3*L/min*t)-ln(2000L)]=ln(m)-ln(90kg)$

$-ln[(2000L+3*L/min*t)/2000L]=ln(m/90kg)$

$m=90kg*[2000L/(2000L+3*L/min*t)]$

a) Initially: t=0

$m=90kg*[2000L/(2000L+3*L/min*0)]=90kg$

b) t=210 min (3.5 hr)

$m=90kg*[2000L/(2000L+3*L/min*210min)]=68.4kg$

c) If time trends to infinity the division trends to 0 and, therefore, m trends to 0. So, the concentration at infinit time is 0 kg/L.

6 0

3 years ago

A 15.0 L tank of gas is contained at a high pressure of 8.20 x 10^4 torr. The tank is opened and the gas expands into an empty c

Inga [223]

Answer:

20.5torr

Explanation:

Given parameters:

V₁ = 15L

P₁ = 8.2 x 10⁴torr

V₂ = 6 x 10⁴L

Unknown:

P₂ = ?

Solution:

To solve this problem we have to apply the claims of Boyle's law.

Boyle's law is given mathematically as;

P₁ V₁ = P₂V₂

where P₁ is the initial pressure

V₁ is the initial volume

P₂ is final pressure

V₂ is final volume

8.2 x 10⁴ x 15 = P₂ x 6 x 10⁴

P₂ = 20.5torr

5 0

2 years ago