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ArbitrLikvidat [17]
2 years ago
12

How many valence electrons are in each atom? a. potassium C. magnesium b. carbon d. oxygen ​

Chemistry
1 answer:
skad [1K]2 years ago
7 0
Just look it up you’ll get the answers faster
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The solid form of a substance is usually more dense than its liquid and gaseous forms. Similarly the liquid form is usually more
bonufazy [111]
A is the answer.

Ice is solid, however, water is liquid. Yet ice still floats which is less dense than water.

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3 years ago
Which statement about atoms is correct
lesya [120]

Answer:Protons are positively charged is the correct statement about an atom

I've also corrected the other statements

Atoms contain protons and neutrons in their nucleus

Neutrons posses no charge and are neutral

The nucleon number is the total number of protons and neutrons in a nucleus

6 0
3 years ago
A 3.82-g sample of magnesium nitride is reacted with 7.73 g of water. mg3n2 (s) + 3 h2o (â) â 2 nh3 (g) + 3 mgo (s) the yield of
horrorfan [7]
The reaction is properly written as

Mg₃N₂ (s) + 3 H₂O (l) --> 2 NH₃<span> (g) + 3 MgO (s) 

Molar mass of Mg</span>₃N₂ = 100.95 g/mol
Molar mass of H₂O = 18 g/mol
Molar mass of MgO = 40.3 g/mol

Moles Mg₃N₂: 3.82/100.95 = 0.0378
Moles H₂O: 7.73/18 = 0.429 

Theo H₂O required for available Mg₃N₂: 0.0378*3/1 = 0.1134 mol
Hence, the limiting reactant is Mg₃N₂.
Thus,

Theoretical Yield = 0.0378 mol Mg₃N₂ * 3 mol MgO/Mg₃N₂ * 40.3 g/mol
Theo Yield = 4.57 g

Percent Yield = Actual Yield/Theo Yield * 100
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5 0
3 years ago
How are t cells and b cells same
tigry1 [53]
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5 0
3 years ago
Read 2 more answers
What is the empirical formula for a compound that is 29.44\% calcium, 23.55% sulfur, and 47.01% oxygen? This compound is a commo
PSYCHO15rus [73]

Answer:

Empirical formula is CaSO₄.

Explanation:

Given data:

Percentage of calcium =29.44%

Percentage of sulfur = 23.55%

Percentage of oxygen = 47.01%

Empirical formula = ?

Solution:

Number of gram atoms of Ca = 29.44 / 40 = 0.74

Number of gram atoms of S = 23.55 / 32 = 0.74

Number of gram atoms of O = 47.01 / 16 = 3

Atomic ratio:

            Ca                      :        S                :         O

           0.74/0.74           :     0.74/0.74      :       3/0.74

               1                     :          1              :          4

Ca : S : O = 1 : 1 : 4

Empirical formula is CaSO₄.

3 0
3 years ago
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