<u>Answer:</u>
1. In Glucose: C : H : O = 1 : 2 : 1
2. In Sulfuric acid: H : S : O = 2 : 1 : 4
3. In Butene: C : H = 1 : 2
<u>Explanation:</u>
Mole ratio is defined as the ratio of amounts in moles present in a compound. Simplest mole ratio basically means that the moles are present in the least whole number ratio.
- In Glucose,
Moles of Carbon atom = 6
Moles of Hydrogen atom = 12
Moles of Oxygen atom = 6
Mole ratio of the atoms: C : H : O :: 6 : 12 : 6
Making this, the simplest mole ratio C : H : O = 1 : 2 : 1
- In Sulfuric acid,
Moles of Sulfur atom = 1
Moles of Hydrogen atom = 2
Moles of Oxygen atom = 4
Mole ratio of the atoms: H : S : O = 2 : 1 : 4
- In Butene,
Moles of Carbon atom = 4
Moles of Hydrogen atom = 8
Mole ratio of the atoms: C : H = 1 : 2
Answer:
Mass of magnesium oxide formed = 35.1 g
Explanation:
Given data:
Mass of Mg = 20.9 g
Mass of O₂ = 15.2 g
Mass of magnesium oxide formed = ?
Solution:
Chemical equation:
2Mg + O₂ → 2MgO
Number of moles of Mg:
Number of moles = mass/molar mass
Number of moles = 20.9 g/ 24 g/mol
Number of moles = 0.87 mol
Number of moles of O₂:
Number of moles = mass/molar mass
Number of moles = 15.2 g/ 32 g/mol
Number of moles = 0.475 mol
Now we will compare the moles of MgO with magnesium and oxygen.
Mg : MgO
2 : 2
0.87 : 0.87
O₂ : MgO
1 : 2
0.475 : 2/1×0.475 = 0.95
Number of moles of MgO formed by Mg are less thus Mg will limiting reactant.
Mass of MgO:
Mass = number of moles × molar mass
Mass = 0.87 mol × 40.3 g/mol
Mass = 35.1 g
<h3>
<u>ANSWER</u> </h3>
4. O²-
<h3>
<u>EXPLANATION</u> </h3>
O²- has 16 electrons while Ne has 18 electrons. O²- is a molecule that has one electron added to each atom, meaning that there are two extra electrons which makes O²- the same electron configuration as of Ne atom.
The empirical formula of compound X is
From the analysis, we have the following information about the composition of compound X by mass; 40.00% C, 6.71% H, and 53.29% O
Hence, to find the empirical formula of compound X ;
C - 40.00/12 H - 6.71/1 O - 53.29/16
C - 3.33 H - 6.71 O - 3.33
Dividing through by the lowest ratio;
C - 3.33/3.33 H - 6.71/3.33 O - 3.33/3.33
C - 1 H - 2 O - 1
Empirical formula of the compound X is CH2O
Learn more; brainly.com/question/1363167
Answer:
False.
Explanation:
Rate of reaction also depends on the number of collision that is being happening in reacting molecules. So concentration of the reactants is also important to decide the rate of reaction.
The rate of reaction is dependent on the concentration as well.
As the concentration of reactants decreases with time number of collisions also decreases .
