<u>Answer:</u> The mass of water required will be 10.848 g.
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
......(1)
Given mass of nitric acid = 75.9 g
Molar mass of nitric acid = 63 g/mol
Putting values in above equation, we get:
For the given chemical equation:
By Stoichiometry of the reaction:
2 moles of nitric acid is produced by 1 mole of water.
So, 1.204 moles of nitric acid will be produced by = of water.
Now, calculating the amount of water, we use equation 1:
Moles of water = 0.602 mol
Molar mass of water = 18.02 g/mol
Putting values in equation 1, we get:
Hence, the mass of water required will be 10.848 g.