Answer:
21/2 we get remainder 1
10/2 we get remainder 0
5/2 we get remainder 1
2/2 we get remainder 0
1. Now take the 1
The answer to the question is
(21)10=(10101)2
Answer:
No puedo entenderte solo en español
Answer:
Energy Saved = 6.93 x 10⁹ Btu
Cost Saved = $ 30145.5
Explanation:
The energy generated by each boiler can be given by the following formula:
![Annual\ Energy = (Heat\ In)(Combustion\ Efficiency)(Operating\ Hours)](https://tex.z-dn.net/?f=Annual%5C%20Energy%20%3D%20%28Heat%5C%20In%29%28Combustion%5C%20Efficiency%29%28Operating%5C%20Hours%29)
Now, the energy saved by the increase of efficiency through tuning will be the difference between the energy produced before and after tuning:
![Energy\ Saved = (Heat\ In)(Efficiency\ After\ Tune - Efficiency\ Before\ Tune)(Hours)](https://tex.z-dn.net/?f=Energy%5C%20Saved%20%3D%20%28Heat%5C%20In%29%28Efficiency%5C%20After%5C%20Tune%20-%20Efficiency%5C%20Before%5C%20Tune%29%28Hours%29)
![Energy\ Saved = (5.5\ x\ 3\ x\ 10^{6}\ Btu/h)(0.8-0.7)(4200\ h)](https://tex.z-dn.net/?f=Energy%5C%20Saved%20%3D%20%285.5%5C%20x%5C%203%5C%20x%5C%2010%5E%7B6%7D%5C%20Btu%2Fh%29%280.8-0.7%29%284200%5C%20h%29)
<u>Energy Saved = 6.93 x 10⁹ Btu</u>
Now, for the saved cost:
![Cost\ Saved = (Energy\ Saved)(Unit\ Cost)\\Cost\ Saved = (6.93\ x\ 10^{9}\ Btu)(\$4.35/10^{6}Btu)\\](https://tex.z-dn.net/?f=Cost%5C%20Saved%20%3D%20%28Energy%5C%20Saved%29%28Unit%5C%20Cost%29%5C%5CCost%5C%20Saved%20%3D%20%286.93%5C%20x%5C%2010%5E%7B9%7D%5C%20Btu%29%28%5C%244.35%2F10%5E%7B6%7DBtu%29%5C%5C)
<u>Cost Saved = $ 30145.5</u>
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