Answer: General purpose branch circuit
Explanation:
General purpose branch circuit are the type of circuits that are used mainly to supply light to two or more receptacle outlets for small appliances. This circuits are about 120v can be used either in residential, commercial and industrial buildings.
Answer:
<u>construction workers</u>
Explanation:
A construction worker is usually someone with the technical skills and abilities needed to manually construct physical infrastructures.
Since a walkway is an infrastructure, hiring skilled construction workers should perform the project of building the series of walkways within the large garden apartment.
Problem Solvers
Explanation:
Engineers find problems in the world, and then they find solutions for them.
Answer:
E=52000Hp.h
E=38724920Wh
E=1.028x10^11 ftlb
Explanation:
To solve this problem you must multiply the engine power by the time factor expressed in h / year, to find this value you must perform the conventional unit conversion procedure.
Finally, when you have the result Hp h / year you convert it to Ftlb and Wh
![E=(12.5hp)(\frac{16h}{day} )(\frac{5 days}{week} )(\frac{52week}{year} )\\](https://tex.z-dn.net/?f=E%3D%2812.5hp%29%28%5Cfrac%7B16h%7D%7Bday%7D%20%29%28%5Cfrac%7B5%20days%7D%7Bweek%7D%20%29%28%5Cfrac%7B52week%7D%7Byear%7D%20%29%5C%5C)
E=52000Hp.h
![E=52000Hp.h(\frac{744.71Wh}{Hp.h} )\\](https://tex.z-dn.net/?f=E%3D52000Hp.h%28%5Cfrac%7B744.71Wh%7D%7BHp.h%7D%20%29%5C%5C)
E=38724920Wh
![E=52000Hph(\frac{1977378.4 ft lb}{1Hph}](https://tex.z-dn.net/?f=E%3D52000Hph%28%5Cfrac%7B1977378.4%20%20ft%20lb%7D%7B1Hph%7D)
E=1.028x10^11 ftlb
Answer:
Q=67.95 W
T=119.83°C
Explanation:
Given that
For air
Cp = 1.005 kJ/kg·°C
T= 20°C
V=0.6 m³/s
P= 95 KPa
We know that for air
P V = m' R T
95 x 0.6 = m x 0.287 x 293
m=0.677 kg/s
For gas
Cp = 1.10 kJ/kg·°C
m'=0.95 kg/s
Ti=160°C ,To= 95°C
Heat loose by gas = Heat gain by air
[m Cp ΔT] for air =[m Cp ΔT] for gas
by putting the values
0.677 x 1.005 ( T - 20)= 0.95 x 1.1 x ( 160 -95 )
T=119.83°C
T is the exit temperature of the air.
Heat transfer
Q=[m Cp ΔT] for gas
Q=0.95 x 1.1 x ( 160 -95 )
Q=67.95 W