Answer:
Mechanical Efficiency = 83.51%
Explanation:
Given Data:
Pressure difference = ΔP=1.2 Psi
Flow rate = 
Power of Pump = 3 hp
Required:
Mechanical Efficiency
Solution:
We will first bring the change the units of given data into SI units.
Now we will find the change in energy.
Since it is mentioned in the statement that change in elevation (potential energy) and change in velocity (Kinetic Energy) are negligible.
Thus change in energy is
As we know that Mass = Volume x density
substituting the value
Energy = Volume * density x ΔP / density
Change in energy = Volumetric flow x ΔP
Change in energy = 0.226 x 8.274 = 1.869 KW
Now mechanical efficiency = change in energy / work done by shaft
Efficiency = 1.869 / 2.238
Efficiency = 0.8351 = 83.51%
Answer:
Explanation:
B. you would grab the plug closest to the outlet
Answer:
your answer is correct
Explanation:
You have the correct mapping from inputs to outputs. The only thing your teacher may disagree with is the ordering of your inputs. They might be written more conventionally as ...
A B Y
0 0 1
0 1 0
1 0 0
1 1 1
That is, your teacher may be looking for the pattern 1001 in the last column without paying attention to what you have written in column B.
Answer:
def filter_only_certain_strings(data_list):
new_list = []
for data in data_list:
# fix here. change >= to >
# because we want to return strings longer than 5 characters in length.
if type(data) == str and len(data) > 5:
new_list.append(data)
return new_list
Explanation:
def filter_only_certain_strings(data_list):
new_list = []
for data in data_list:
# fix here. change >= to >
# because we want to return strings longer than 5 characters in length.
if type(data) == str and len(data) > 5:
new_list.append(data)
return new_list
